Your answer is x= 1/2, this is because to get the x alone you need to move the 2 so you divide 2x by to and you have to do the same to the other side so 1/2, and you get x=1/2
Answer:
(a) 
(b) 
(c) 
(d) 
(e) 
Explanation:
To calculate de pH of an acid solution the formula is:
![pH = -Log ([H^{+}]) = 1](https://tex.z-dn.net/?f=pH%20%3D%20-Log%20%28%5BH%5E%7B%2B%7D%5D%29%20%3D%201)
were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.
(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.
(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:
![K_{w} =[H^{+} ][OH^{-}]=10^{-14}](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%5BH%5E%7B%2B%7D%20%5D%5BOH%5E%7B-%7D%5D%3D10%5E%7B-14%7D)
clearing the ![[H^{+} ]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D)
![[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B%5BOH%5E%7B-%7D%5D%7D)
(d) is a weak base so it is necessary to solve the equilibrium first, knowing 
The reaction is
→
so the equilibrium is

clearing the <em>x</em>

![x=[H^{+}]=4.93x10^{-10}](https://tex.z-dn.net/?f=x%3D%5BH%5E%7B%2B%7D%5D%3D4.93x10%5E%7B-10%7D)
There are 54 Protons in Xe and 77 Neutrons in Xe.
2KCIO3=2KCL+302
Hope you enjoy :)