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kramer
3 years ago
13

A 60 kg student is standing atop a spring in an elevator that is accelerating upward at 3.0 m/s2. The spring constant is 2.5 x 1

03 N/m. By how much is the spring compressed?
Physics
1 answer:
dimaraw [331]3 years ago
6 0

the spring will be compressed by 0.3072 m

Explanation:

acceleration of elevator=3 m/s²

mass of student= 60 Kg

spring constant=2.5 x 10³ N/m

the force on the student is given by F = m ( g +a)

F=60 (9.8+3)

F=768 N

now the formula for spring force is given by

F= k x

768= 2.5 x 10³ (x)

x=0.3072 m

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3 years ago
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0.5 m/s².

Explanation:

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Initial velocity (u) = 0 m/s

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a = (v – u) / t

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u is the initial velocity.

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2 years ago
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