F=ma
Force is 50N. Acceleration is 25 m/s^2.
50N=m*25 m/s^2
Divide both sides by 25.
mass=2 kg
Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;

Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;


v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
Answer:
i belive 1 m/s
Explanation:
dividing displacement from time it should be 1 cuz 5/5 is 1
please tell me if right!
The focal length of the converging lens based on the arrow placed 3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.
<h3>
Focal length of the converging lens</h3>
The focal length of the converging lens is determined by applying the following converging lens formula.
1/f = 1/v + 1/u
where;
- v is the image distance = 3 cm
- u is the object distance = 3 cm
- f is the focal length = ?
1/f = 1/3 + 1/3
1/f = 2/3
f = 3/2
f = 1.5 cm
Thus, the focal length of the converging lens is 1.5 cm.
Learn more about converging lens here: brainly.com/question/22394546