When AgNO₃ solution is added to mixture of NaNO₃ and NaCl, it reacts with NaCl and gives precipitate of AgCl, which is white solid. The reaction takes place in 1:1 stoicheometric ratio as per the following balanced reaction:
NaCl + AgNO₃→ AgCl ↓ + NaNO₃. As per reaction 1 mole NaCl reacts with 1 mole AgNO₃ and gives of solid precipitate of 1 mole AgCl.
0.641 g= = 4.47 X
mole of solid AgCl is produced. This indicates 4.47 X
mole NaCl =
g of Nacl reacts to give 0.641 g of AgCl. So, mass percentage of NaCl present in mixture=
= 17.33 %.