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emmainna [20.7K]
1 year ago
6

Explain the impact that changing the temperature has on a system in a state of dynamic equilibrium. what will happen when the te

mperature of an exothermic reaction mixture at equilibrium is increased?
Chemistry
1 answer:
NNADVOKAT [17]1 year ago
6 0

An endothermic reaction is favored by raising the temperature of a system in dynamic equilibrium. The mechanism absorbs the increased heat to offset the alteration you made. An exothermic reaction is favored by a system's temperature falling while it is in dynamic equilibrium.

<h3>Which of these reactions is endothermic?</h3>

Any chemical process that takes heat from its surroundings is said to be endothermic. The reaction's activation energy comes from the energy that was absorbed. This kind of reaction is characterized by its icy sensation.

<h3>How does an exothermic reaction work?</h3>

An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.

<h3>What kind of reaction is an exothermic reaction?</h3>

Materials like hydrocarbons reacting with oxygen to produce combustion products like water and carbon dioxide is an example of an exothermic process.

learn more about endothermic reaction here

<u>brainly.com/question/6506846</u>

#SPJ4

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What is true about water that is freezing?
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The value of the rate constant for a gas phase reaction can be changed by increasing the A. temperature of the reaction vessel.
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temperature of the reaction vessel

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3 0
3 years ago
Calculate the volume in milliliters of a iron(II) bromide solution that contains of iron(II) bromide . Round your answer to sign
miv72 [106K]

This is an incomplete question, here is a complete question.

Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.

Answer  : The volume of iron(II) bromide solution is, 2.13\times 10^2mL

Explanation : Given,

Concentration of iron(II) bromide = 1.29 mo/L

Moles of iron(II) bromide = 275 mmol = 0.275 mol

conversion used : 1 mmol = 0.001 mol

Now we have to calculate the volume of iron(II) bromide.

\text{Volume of iron(II) bromide}=\frac{Moles of iron(II) bromide}}{\text{Concentration of iron(II) bromide}}

Now put all the given values in this formula, we get:

\text{Volume of iron(II) bromide}=\frac{0.275mol}{1.29mol/L}=0.213L=2.13\times 10^2mL

Thus, the volume of iron(II) bromide solution is, 2.13\times 10^2mL

5 0
3 years ago
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