Answer:
The type of bond between the Oxygen atom and the hydrogen is Covalent
this is because the 2 electrons are being shared by both hydrogen and oxygen
The type of bond this molecule makes as a whole is called a Hydrogen Bond
A hydrogen bond is formed because of the partial +ve and -ve charge in a molecule
The cause of the partial +ve and -ve charge is the comparatively high electronegativity of oxygen which makes the electron get attracted towards the oxygen atom while the hydrogens try to maintain the maximum distance from the lone pairs due to repulsion
Hope it helped
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The alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.
<h3>What are the properties of alkali metals?</h3>
The alkali metals have the high thermal and electrical conductivity. It has high lustre, ductility, and malleability as compared to other materials. Each alkali metal atom has one electron in its outermost shell which make more reactive.
So we can conclude that the alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.
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Answer:
12.99
Explanation:
<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of KOH: 716. mg (0.716 g)
- Volume of the solution: 130. mL (0.130 L)
Step 2: Calculate the moles corresponding to 0.716 g of KOH
The molar mass of KOH is 56.11 g/mol.
0.716 g × 1 mol/56.11 g = 0.0128 mol
Step 3: Calculate the molar concentration of KOH
[KOH] = 0.0128 mol/0.130 L = 0.0985 M
Step 4: Write the ionization reaction of KOH
KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)
The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M
Step 5: Calculate the pOH
We will use the following expression.
pOH = -log [OH⁻] = -log 0.0985 = 1.01
Step 6: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -1.01 = 12.99
