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Bond [772]
3 years ago
6

Emission results in the release of energy without any apparent change in mass or nuclear charge.

Chemistry
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

gamma ray

Explanation:

Gamma emission results in the release of energy without any apparent change in mass or nuclear charge.

Properties of Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

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How many neutrons and protons (nucleons) does an atom with
mezya [45]

Answer:

E

Explanation:

None of the above

The atom with the symbol S is called sulphur Sulphur has atomic number 16 which means that it has 16 protons. Sulphur-32 has 32 nucleons - 16 protons and 16 neutrons.Sulfur is a chemical element  It is  nonmetallic. Under normal conditions, sulfur atoms form cyclic octatomic molecules with a chemical formula S8. Elemental sulfur is a bright yellow, crystalline solid at room temperature.

4 0
3 years ago
An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
3 years ago
The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
What is chemical reaction ?​
butalik [34]

<u><em>Answer: Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products.</em></u>

Explanation:

7 0
3 years ago
What is a warm front
Galina-37 [17]

Answer:the Boundary of an advancing mass of warm air, in particular the leading edge of the warm sector of a low-pressure system.

Explanation:

3 0
3 years ago
Read 2 more answers
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