Question

Kevin had six nickels and 4 dimes in his pocket. If he took out one coin and then a second coin without replacing the first coin-- a) what is the probability that both coins were nickels. b) what is the probability that both coins were dimes. c) what is the probability that the first coin was a nickel and the second a dime

Answer 1

Alright so A is 6/10 * 5/9 = 1/3
B is 4/10 * 7/9 = 2/15
C is 6/10 * 4/9 = 4/15

I hope this helps