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ankoles [38]
3 years ago
11

Kevin had six nickels and 4 dimes in his pocket. If he took out one coin and then a second coin without replacing the first coin

-- a) what is the probability that both coins were nickels. b) what is the probability that both coins were dimes. c) what is the probability that the first coin was a nickel and the second a dime

Mathematics
1 answer:
Umnica [9.8K]3 years ago
4 0
Alright so A is 6/10 * 5/9 = 1/3
B is 4/10 * 7/9 = 2/15
C is 6/10 * 4/9 = 4/15

I hope this helps


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<u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u><u>-</u>

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#IhopeThisHelp

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