$y=\sqrt[3]{-x}-3\ and\ x\in(-8;\ 8)\\\\subtitute\ x=-8\ and\ x=8\ to\ the\ equation:\\\\y=\sqrt[3]{-(-8)}-3=\sqrt[3]8-3=2-3=-1\\\\y=\sqrt[3]{-8}-3=-2-3=-5\\\\Answer:\boxed{\{y|-5 \ \textless \ y \ \textless \ -1\}}\to\fbox{b.}$

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4 years ago

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A machine produces small cans that are used for baked beans. The probabil- ity that the can is in perfect shape is 0.9. The prob

Elis [28]

Answer:

0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Shipped for use

Event B: Perfect shape

Probability of being shipped for use:

Perfect shape(0.9 probability) or unnoticeable dent(0.02 probability). So

$P(A) = 0.9 + 0.02 = 0.92$

Being shipped for use and being in perfect shape.

0.9 probability, so $P(A \cap B) = 0.9$

What is the probability that a can that gets shipped for use will be of perfect shape?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.9}{0.92} = 0.9783$

0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape

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3 years ago

3576 divided by 9.1 show steps

bekas [8.4K]

392.967032967
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4 years ago

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