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4 years ago

3(2v + 1)= -15(v5 + 16)

1 answer:

6 0

<span>3(2v + 1)= -15(5v + 16)
6v + 3 = -75v - 240 (Add 75v onto each side)
+75v +75v
81v + 3 = 240 (Subtract 3 on each side)
-3 -3
81v = -243

v = -3

</span>

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The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid

MaRussiya [10]

Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = $x$

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = $12+x$

As we know:

$Area\ of\ rectangle=length\times breadth$

$85=(12+x)x\\\\85=12x+x^{2} \\$

Subtracting both sides by 85

$x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5$

As width can never be in negative, hence width of a rectangular wall of a barn = $x$ = 5 feet

Length of a rectangular wall of a barn = $12+x=12+5=17\ feet$

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

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Find the midpoint of the line segment joining the points. (6, -5), (6, 3)

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Step-by-step explanation:

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Answer:

If we have two figures, F and F'

Such that if we start with F, and dilate it with a scale factor K, we get F'.

We will have:

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Then if F has s₁, s₂, ..., sₙ sides, the sides of F' will be:

K*s₁, K*s₂, ..., K*sₙ

The ratio between correspondent sides will be equal to K

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In the case of the area, because we usually multiply a measure by another, a factor K^2 will appear, and the quotient between the areas is K^2

And finally, for the volumes, the ratio will be K^3

a) The ratio of corresponding lengths is K, in this case is 5/2

b) The ratio of the perimeters is K, in this case is 5/2

c) The ratio of the areas is K^2, in this case is (5/2)^2 = 25/4

d) The ratio of the areas is K^3, in this case is (5/2)^3 = 125/8

e) Two figures are similar if the figures have the same shape, then the corresponding angles are exactly the same, then the ratio of corresponding angle measures is 1.

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