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Studentka2010 [4]
2 years ago
11

I need help please I need it ASAP

Mathematics
1 answer:
Bess [88]2 years ago
7 0

Answer:

Step-by-step explanation:

Answers and explanations in attachment.  Problem 29 was cut off a bit.  I assumed the question was what percent of the total are cubs.

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kow [346]
The first answer
-40y3/x5
8 0
3 years ago
Two consecutive negative integers have a product of 2. what are the integers ?
MrRissso [65]

product is multiplication

 2 negative numbers multiplied by each other equal 2

 since it is multiplication the numbers would need to be 2 or less

 therefore the 2 numbers are -1 and -2


-1 * -2 = 2

 

6 0
3 years ago
Write number to make each line have the sum 7
DochEvi [55]
Write each line to make the sum 7 it say I can't tell y'all the answer dang alot of people need help I got 18 seconds to tell yall
8 0
3 years ago
does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
3 years ago
How many passwords of 5 characters (numbers or letters) can be created if repeats are allowed
alex41 [277]

Answer:

at least 290,000

Step-by-step explanation:

Why is this a question

4 0
3 years ago
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