Answer: A B
Group 1 0.25 0.75
Group 2 0.44 0.56
Step-by-step explanation:
Since we have given that
Number of people of A in group 1 = 15
Number of people of B in group 1 = 45
Total number of people in group 1 is given by

Relative frequency of people of A in Group 1 is given by

Relative frequency of people of B in Group 1 is given by

Similarly, Number of people of A in group 2 = 20
Number of people of B in group 2 = 25
Total number of people in group 2 is given by

Relative frequency of people of A in Group 2 is given by

Relative frequency of people of B in Group 2 is given by

Hence, A B
Group 1 0.25 0.75
Group 2 0.44 0.56
The point of elimination is to have one variable so example
3x + 2y = 4
7X + 3y = 5
1) Try to find a way to have one variable
7(3x + 2y = 4) ----> 21x + 14y = 28
-3(7x+ 3y = 5) -----> -21x -9y = -15
2) add
0 + 5y = 13
3) solve for the last variable
5y = 13
y = 13/5 = 2 3/5 = 2.8
4) Subsitute the variable to get the other one
3x + 2(2.8) = 4
3x + 5.6 = 4
3x = -1.6
x = 0.533333333 (continue)
The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)
Hope you understand!!
Th three numbers he could of had on his uniform are 60 30 or 90
Answer:
450/500 = 0.9sorry if it's wrong
Step-by-step explanation: