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pashok25 [27]
3 years ago
6

Can someone help me with the working out please its due Tomorrow

Mathematics
1 answer:
slavikrds [6]3 years ago
3 0
1) 12p+12q 2) 11p-11q 3)2p-10q
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The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe
alexgriva [62]
Let the width be x.

Length is 8 feet more than width. Length = x + 8

Area = x(x + 8)

width increased by 4, that is,  (x + 4)
Length decreased by 5,    (x + 8 - 5) = (x + 3)

Area  = (x + 4)(x +3)

Area remains the same

x(x + 8) = (x+4)(x +3)

x² + 8x =   x(x +3) + 4(x +3)

 x² + 8x =   x² +3x + 4x +12

x² + 8x =   x² +7x +12        Eliminate x² from both sides

8x = 7x + 12

8x - 7x = 12

x = 12

Dimensions of original rectangle :  x,  x + 8

12, 12 +8 =   12, 20

Original rectangle is   20 feet   by 12 feet 
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Answer:

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Step-by-step explanation:

white socks: black socks

1  :3

We have 12 white socks so we multiply each term by 12

1*12 : 3*12

12:36

We have 36 black socks

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Step-by-step explanation:

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