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3 years ago

Please help i need to correct

Chemistry

1 answer:

lisabon 2012 [21]3 years ago

5 0

It would undergo a physical change because a change of matter is always a physical change because it is not changing the actual substance. It is the same substance, it has just changed the movement of its particles. I hope this helps! :)

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Highlighted answer is wrong just need someone to explain it if you can!❤️

lora16 [44]

Answer:

2.7 x 10^-1

Explanation:

The places you move to the left are added to the 10 in negative exponential

7 0

3 years ago

What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim

Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means $P_{2} =\frac{P_{1} }{10}$

Given the volume of the system increased by 5 times which means $V_{2} =5\times V_{1}$

Given final temperature $T_{2}=150K$

Let the initial temperature be $T_{1}$

We know that PV=nRT

As n and R are constant $\frac{PV}{T}=constant$

$\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}$

$T_{1} =2\times T_{2}$

T1=300K

8 0

3 years ago

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

Inessa05 [86]

Answer:

0.0613 L

Explanation:

Given data

Initial pressure (P₁): 1.00 atm

Initial volume (V₁): 1.84 L

Final pressure (P₂): 30.0 atm

Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

6 0

4 years ago

Determine the freezing point of 0.368 kg of H2O with 11.85 g of C2H5OH where the kf is 1.86 C/m.

saveliy_v [14]

We will use the formula for freezing point depression :

but first, we need to get the molality m of the solution:

- molality m = moles of C2H5OH / mass of water Kg

when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH

= 11.85 g / 46 g/mol

= 0.258 moles

and when we have the mass of water Kg = 0.368 Kg

so, by substitution on the molality formula:

∴ molality m = 0.258 moles / 0.368 Kg

= 0.7 mol/Kg

and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1

and when Kf is given = 1.86 C/m

so by substitution on ΔTf formula:

when ΔTf = i Kf m

∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg

= 1.302 °C

5 0

3 years ago

What type of reaction occurs when energy is released?

Charra [1.4K]

Exothermic is a chemical reaction that releases energy.

5 0

3 years ago