Question

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm , what was the volume of the sample

Answer 1

Answer:

0.0613 L

Explanation:

Given data

• Initial pressure (P₁): 1.00 atm

• Initial volume (V₁): 1.84 L

• Final pressure (P₂): 30.0 atm

• Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L