A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

Question

3 years ago

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A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm , what was the volume of the sample

Chemistry

1 answer:

Inessa05 [86] · Answer 1 · 2021-11-25T22:22:31+03:00

Answer:

0.0613 L

Explanation:

Given data

Initial pressure (P₁): 1.00 atm

Initial volume (V₁): 1.84 L

Final pressure (P₂): 30.0 atm

Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L