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denis23 [38]
3 years ago
13

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm , what was the volume of the sample
Chemistry
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

0.0613 L

Explanation:

Given data

  • Initial pressure (P₁): 1.00 atm
  • Initial volume (V₁): 1.84 L
  • Final pressure (P₂): 30.0 atm
  • Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

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Explanation:

Relation between length of a curve and angle is as follows.

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If curve has a degree of curvature D_{a} for standard length s, then

               R = \frac{s}{D_{a}} \times \frac{180}{\pi}   ........... (2)

Now, substitute the value of R from equation (2) into equation (1) as follows.

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thus, we can conclude that the length of the curve is 452 m.

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