They have the same number of valence electrons / outermost shell electrons.
Answer:
13.5 * 10^-2 g
Explanation:
What we know:
Balanced Equation: 3Ba+Al2(SO4)3 -->2Al+3BaSO4,
Grams of Ba: 1
Grams of Al2(SO4)3: 1.8g
Calculate the # of moles of Ba and Al2(SO4)3:
1g Ba/137.3 = 7.3 *10^-3 mol Ba
1.8g Al2(SO4)3/ 342 = 5.3 *10^-3 mol Al2(SO4)3
Find the limiting reactant:
Ba has a coefficient of 3 in the balanced equation, so we divide the # of moles of Ba by 3 to get... 7.3 *10^-3 mol Ba/3 = 2.43 *10^-3
Al2(SO4)3 has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 *10^-3
2.43 *10^-3 is smaller than 5.3 *10^-3, therefore Ba is the limiting reactant.
finally, we just find the number of moles of Al
The ratio of Al to Ba is 2:3 so...
7.3 * 10^-3 * (2/3) = 5 *10^-3 mol Al
CONVERT TO GRAMS
5 *10^-3 mol Al * 27 = 13.5 * 10^-2 g
<u>Hope that was helpful! </u>
Lead is the Carbon family of the periodic table.
Answer:
<em>Nitrogen = 17.07%</em>
Explanation:
We are asked to calculate the percentage by mass of nitrogen in Ca(NO3)2.
The molar mass of calcium nitrate is 164,088 g/mol.
In this 164.088 g/mol there are 2 nitrogen atoms.
Molar mass of nitrogen = 14,0067 g/mol
% Nitrogen = molar mass of N/total molar mass of the compound
% Nitrogen =[(2 x 14.0067)/164.088]*100
% Nitrogen = 17.07%
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