Ask question

Ask question

All categories

3 years ago

13

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm , what was the volume of the sample

1 answer:

Inessa05 [86]3 years ago

6 0

Answer:

0.0613 L

Explanation:

Given data

Initial pressure (P₁): 1.00 atm

Initial volume (V₁): 1.84 L

Final pressure (P₂): 30.0 atm

Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

You might be interested in

Si Units Worksheet. Use si units to complete

Keith_Richards [23]

$\\ \bull\tt\dashrightarrow 2000m=2km$

$\\ \bull\tt\dashrightarrow 9000mL=9L$

$\\ \bull\tt\dashrightarrow 6L=6000mL$

$\\ \bull\tt\dashrightarrow 6cm=60mm$

$\\ \bull\tt\dashrightarrow 1000m=1km$

$\\ \bull\tt\dashrightarrow 50mm=5cm$

$\\ \bull\tt\dashrightarrow 4L=4000mL$

$\\ \bull\tt\dashrightarrow 10000g=10kg$

$\\ \bull\tt\dashrightarrow 10000m=10km$

$\\ \bull\tt\dashrightarrow 4000g=4kg$

$\\ \bull\tt\dashrightarrow 9km=9000m$

$\\ \bull\tt\dashrightarrow 3kg=3000g$

$\\ \bull\tt\dashrightarrow 90mm=9cm$

$\\ \bull\tt\dashrightarrow 4km=4000m$

$\\ \bull\tt\dashrightarrow 2000g=2kg$

$\\ \bull\tt\dashrightarrow 400cm=4m$

$\\ \bull\tt\dashrightarrow 3km=3000m$

$\\ \bull\tt\dashrightarrow 2cm=20mm$

$\\ \bull\tt\dashrightarrow 9000g=9kg$

8 0

3 years ago

Given the equation: HCl + Na2SO4 → NaCl + H2SO4, if you start with 8 moles of hydrochloric acid, how many grams of sulfuric acid

Simora [160]

Answer:

392g sulfuric acid are produced

Explanation:

Based on the balanced equation:

2HCl + Na2SO4 → 2NaCl + H2SO4

<em>2 moles of HCl produce 1 mole of sulfuric acid</em>

<em />

To solve the problem we need to find the moles of sulfuric acid produced based on the chemical equation. Then, using its molar mass -<em>Molar mass H2SO4 = 98g/mol- </em>we can find the mass of sulfuric acid produced:

<em>Moles sulfuric acid:</em>

8mol HCl * (1mol H2SO4 / 2mol HCl) = 4 mol H2SO4

<em>Mass sulfuric acid:</em>

4mol H2SO4 * (98g / mol) =

392g sulfuric acid are produced

4 0

3 years ago

Noah and Nina are 15 m apart in a closed room. Noah says the same sentence twice. The first time, Nina does not hear the sound,

In-s [12.5K]

The air molecules in the compressions of the second wave are denser, so the sound is louder.

<h3>What is a sound wave?</h3>

Sound waves are longitudinal waves that travel through a medium like air or water.

In a closed room, Noah and Nina are sitting 15 m apart.

As Noah says the same sentence twice, Nina does not hear the sound the first time but she does hear the sentence the second time.

This happens as the air molecules in the compressions of the second wave are denser. As a result, the sound is louder.

The correct option is ''The air molecules in the compressions of the second wave are denser, so the sound is louder''.

Learn more about the sound wave here:

brainly.com/question/1554319

#SPJ1

5 0

1 year ago

Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that

adelina 88 [10]

Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

<u>Step -1:</u> Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

<u>Step -2:</u> Formation terminal alkyne to nonterminal alkynes.

<u>Step -3:</u> Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

8 0

3 years ago

At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat

wariber [46]

Answer:

0.808 M

Explanation:

Using Raoult's Law

$\frac{P_s}{Pi}= x_i$

where:

$P_s$ = vapor pressure of sea water( solution) = 23.09 mmHg

$P_i$ = vapor pressure of pure water (solute) = 23.76 mmHg

$x_i$ = mole fraction of water

∴

$\frac{23.09}{23.76}= x_i$

$x_i = 0.9718$

$x_i+x_2=1$

$x_2 = 1- x_i$

$x_2 = 1- 0.9718$

$x_2 = 0.0282$

$x_i = \frac{n_i}{n_i+n_2}$ ------ equation (1)

$x_2 = \frac{n_2}{n_i+n_2}$ ------ equation (2)

where; $(n_2) =$ number of moles of sea water

$(n_i) =$ number of moles of pure water

equating above equation 1 and 2; we have :

$\frac{n_2}{n_i}$ $= \frac{0.0282}{0.9178}$

$= 0.02901$

NOW, Molarity = $\frac{moles of sea water}{mass of pure water }*1000$

$= \frac{0.02901}{18}*1000$

$= 0.001616*1000$

$= 1.616 M$

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have $\frac{1.616}{2} =0.808 M$

3 0

3 years ago

Read 2 more answers