Answer:
87.37g/mol
A. 116.49g/mol
The molar mass of HZ increased
B. 124.5459 g/mol
The molar mass of HZ increased.
Explanation:
For a neutralisation reaction,
HZ(aq) + NaOH(aq) --> NaZ + H2O(l)
So from the above equation, 1 mole of acid, HZ reacted with 1 mole of base, NaOH to give 1 mole of salt.
Calculating moles of NaOH = molarity(molar concentration) * volume of solution
Molarity is defined as the number of moles of solute per liter of solution.
Moles of NaOH = 33.5 x 10^-3 * 0.1025
= 3.43375 x 10^-3 mol
Using stoichiometry, therefore there were 3.43375 x 10^-3 mol of HZ reacted.
Number of moles = mass/molar mass
Therefore, molar mass = 0.300/3.43375 x 10^-3 mol
= 87.37g/mol
Molar mass of a chemical compound is defined as the mass of a sample of that compound per the amount of substance in that sample in moles.
A. Molar mass = 0.400/3.43375 x 10^-3
= 116.49g/mol
The molar mass of HZ increased.
B. Moles of NaOH = 23.5 x 10^-3 * 0.1025
= 2.40875 x 10^-3 mol
By stoichiometry, therefore 2.40875 x 10^-3 mol of HZ reacted.
Number of moles = mass/molar mass
Therefore, molar mass = 0.300/2.40875 x 10^-3
= 124.5459 g/mol
The molar mass of HZ increased.
