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Oliga [24]
3 years ago
9

Classify these compounds as acid, base, salt, or other. Drag the appropriate items to their respective bins.

Chemistry
2 answers:
sveticcg [70]3 years ago
7 0

Answer:

acid: HCOOH, HNO3, ch3oh

base: NAOH

Salt: NaBr, KCl

Other: co2, NH3

Explanation:

dlinn [17]3 years ago
5 0
Acid: HCOOH , HNO3
base: NaOH, NH3
salt: NaBr, KCl
Other: CH3OH(alcohol), CO2 (can be considered acid when diluted/dissolved in water to form H2CO3)
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moles of Fe and O₂:
12 atoms/(6.02x10^23 atoms/mole)=1.99x10^-23 mol Fe
6 molecules/(6.02x10^23 molecules/mole)=9.967x10^-24 mol <span>O₂
</span>Then you find the limiting reagent by finding how much product each given amount of reactant can make.  Which ever one produces the least amount of product is the limiting reagent.
amount of Fe₂O₃ produced:
<span>(1.99x10^-23 mol Fe)x(2mol/4mol)= 9.967x10^-24mol Fe</span>₂O₃<span> 
</span>(9.967x10^-24 mol O₂)x(2mol/3mol)= 6.645x10^-24 mol Fe₂O₃<span> 
</span>since oxygen produces the leas amount of product, oxygen is the limiting reagent.  since we know that oxygen is the limiting reagent we can use the amount of product formed with oxygen to find the amount of iron used.
6.645x10^-24 mol Fe₂O₃x(4mol/2mol)=1.329x10^-23 mol Fe consumed
<span> find the amount left over by subtracting the original amount of Fe by the amount consumed in the reaction.
</span>1.993x10^-23-1.329x10^-23= 6.645x10^-23mol Fe left
 find the number of atoms by multiplying that by Avogadro's number.
<span>(6.645x10^-23mol)x(6.02x10^23 atoms/mol)=4 atoms
</span>therefore 4 atoms of Fe will be left over after the reaction happens.

I hope this helps.
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dybincka [34]

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