1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nekit [7.7K]
3 years ago
7

A gas-turbine power plant operating on the simple Brayton cycle has a pressure ratio of 7. Air enters the compressor at 0°C and

100 kPa. The maximum cycle temperature is 1500 K. The compressor has an isentropic efficiency of 80 percent, and the turbine has an isentropic efficiency of 90 percent. Assume constant properties for air at 300 K with cv = 0.718 kJ/kg·K, cp = 1.005 kJ/kg·K, R = 0.287 kJ/kg·K, and k = 1.4.a) sketch the T-s diagram for the cycle.
b) if the net power output is 150 MW, determine the volume flow rate of the air into the compressor, in m^3/s.
c) for a fixed compressor inlet velocity and flow area, explain the effect of increasing compressor inlet temperature (i.e., summertime operation versus wintertime operation) on the inlet mass flow rate and the net power output with all other parameters of the problem being the same.

Physics
1 answer:
Ivahew [28]3 years ago
4 0

Answer:

Answers of the Both parts  are in the following attachment

Explanation:

         

You might be interested in
You are riding in a hot air balloon that, relative to the ground, has a velocity of 6.0 m/s due east. You see a hawk moving dire
charle [14.2K]

Answer:Velocity = 6.325m/s

Directional angle= 18.43°

Explanation:

Using Right angle triangle

Let Velocity of ballon&hawk be VHB represent the height of the triangle.

Let Velocity of balloon angle ground be VBG represent adjacent of the triangle.

Let Velocity of hawk and ground BE VHG represent the hypothesis.

Theta = opp/Adj= VHB/VBG

using pythagorean

VHG= SQRT(VHB^2+VBG^2)

VHG= sqrt(2^2+6^2)

VHG= sqrt(4+36)

VHG= 6.325m/s

Tan theta= 2/6

Tan theta =0.3333

Tan^-1 0.3333=18.43°

8 0
3 years ago
Um corpo de massa igual a 2kg move-se com velocidade constante num plano horizontal sem atrito, conforme a figura. Em seguida, e
castortr0y [4]
Only answering to ask a question
4 0
3 years ago
Which events may occur when ocean salinity increases? Check all that apply.
Pavlova-9 [17]
The answer is number two, number four, and number one
3 0
3 years ago
Read 2 more answers
What is the mass of a dog that weighs 382 N?(unit=kg)
Luba_88 [7]

Answer:

The answer to your question is: mass = 38.93 kg

Explanation:

Data

mass = ?

Weight = 382 N

gravity = 9.81 m/s2

Formula

Weight = mass x gravity

mass = weight / gravity

mass = 382 / 9.81         substitution

mass = 38.93 kg           result

6 0
3 years ago
A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

Recall the equation for angular momentum:

L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

I_m = moment of inertia of the merry-go-round (kgm²)

\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

8 0
3 years ago
Other questions:
  • If a net force of 25 N is exerted over a distance of 4 m to the right on a 2 kg mass initially at rest and moves it, what is
    11·1 answer
  • Find the acceleration of a car that can go from rest to 50 km/h in 13 s
    12·1 answer
  • What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per
    12·1 answer
  • Calculate the force when the moment is 40nm and distance is 4m
    6·1 answer
  • the gravitational force exerted on a baseball is 2.21 N down, a pitcher throws the ball horizontally with velocity 18.0 m/s by u
    11·2 answers
  • Mercury is in the 80th position in the periodic table. How many protons does it have?
    12·2 answers
  • PLEASEEE HEPPP!!!!!
    13·2 answers
  • A car, X, with a mass of 1500 kg is moving west with an acceleration of 0.50 m/s2. A second car, Y, of equal mass is heading eas
    8·1 answer
  • Identify two main ideas about the normal force.
    9·1 answer
  • The rate of change of momentum of a body free falling under gravity is equal to its? A. Velocity B. kinetic energy C. power D. w
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!