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3 years ago

Explain why liquids solidify when they are cooled.

Physics

2 answers:

Setler [38]3 years ago

8 0

Because the molecules that move freely begin to compact closer together, with less heat, means less molecular activity.

riadik2000 [5.3K]3 years ago

5 0

Liquids solidify when they are cooled because they have reached their freezing point. For many liquids this is around 32°F or 0°C. Hope you find this information useful.

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In separate experiments, four different particles each start from far away with the same speed and impinge directly on a gold nu

nikitadnepr [17]

Answer:

Potential energy at the beginning: Ui =Qq/R*k ≈ 0 (particles are far apart)

Kinetic energy at the beginning: KEi = $mv^{2}$ /2

Potential energy at the end: Uf =(Qq/r)*k

Kinetic energy at the beginning: KEf = 0

From energy conservation:

r = 2*Qk/ $v^{2}$ *q/m

Ranking of the closest approach to the gold nucleous comes from q/m:

- particle 3 has the smallest q/m = 1/4 ⋅q0/m0 and, hence, comes the closest

- particle 4 has the largest q/m = 4⋅q0/m0 and, hence, comes the last in ranking

- particles 1 and 2 have equal q/m=q0/m0 and, hence, come tie in between particles 3 and 4

Explanation:

Potential energy at the beginning: Ui =Qq/R*k ≈ 0 (particles are far apart)

Kinetic energy at the beginning: KEi = $mv^{2}$ /2

Potential energy at the end: Uf =(Qq/r)*k

Kinetic energy at the beginning: KEf = 0

From energy conservation:

r = 2*Qk/ $v^{2}$ *q/m

Ranking of the closest approach to the gold nucleous comes from q/m:

- particle 3 has the smallest q/m = 1/4 ⋅q0/m0 and, hence, comes the closest

- particle 4 has the largest q/m = 4⋅q0/m0 and, hence, comes the last in ranking

- particles 1 and 2 have equal q/m=q0/m0 and, hence, come tie in between particles 3 and 4

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Explanation:

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Explanation:

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3 years ago

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4 years ago

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th

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Answer:

Explanation:

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = 10 m/s

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3 years ago