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KonstantinChe [14]
3 years ago
15

10 Pts + Brainliest for the best answer.

Mathematics
2 answers:
Harrizon [31]3 years ago
7 0

Answer:

NVU =150

Step-by-step explanation:

WVN + NVU = WVU

We know NVU = 2x+150  and WVU = x+176  and WVN = 26

Substituting these in

26+ 2x+150 = x+176

Combine like terms

176+2x= x+176

Subtract 176 from each side

176-176+2x= x+176-176

2x=x

Subtract x from each side

2x-x = x-x

x=0

NVU = 2x+150

        0+150

NVU =150

JulsSmile [24]3 years ago
6 0

m∠WVU = m∠NVU + m∠WVN

We have m∠WVU = x + 176, m∠NVU = 2x + 150 and m∠WVN = 26°. Substitute:

x + 176 = (2x + 150) + 26

x + 176 = 2x + (150 + 26)

x + 176 = 2x + 176         <em>subtract 176 from both sides</em>

x = 2x        <em>subtract x from both sides</em>

0 = x

m∠NVU = 2x + 150 → m∠NVU = 2(0) + 150 = 0 + 150 = 150

Answer: m∠NVU  = 150°

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A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the fl
ankoles [38]

Answer:

1.

The null hypothesis is H_0: \mu = 4

The alternate hypothesis is H_1: \mu > 4

2.

The p-value of the test is of 0.0045.

3.

The p-value of the test is low(< 0.01), which means that there is enough evidence that the flow rate is more than 4 gallons per minute (gpm) and thus, the pump should be put into service.

Step-by-step explanation:

A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the flow rate be more than 4 gallons per minute (gpm).

At the null hypothesis, we test that the mean is 4, so:

H_0: \mu = 4

At the alternate hypothesis, we test that the mean is more than 4, that is:

H_1: \mu > 4

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

4 is tested at the null hypothesis:

This means that \mu = 4

In an initial study, eight runs were made. The average flow rate was 6.4 gpm and the standard deviation was 1.9 gpm.

This means that n = 8, X = 6.4, s = 1.9

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{6.4 - 4}{\frac{1.9}{\sqrt{8}}}

t = 3.57

P-value of the test:

The p-value of the test is the probability of finding a sample mean above 6.4, which is a right-tailed test with t = 3.57 and 8 - 1 = 7 degrees of freedom.

With the help of a calculator, the p-value of the test is of 0.0045.

3. Should the pump be put into service?

The p-value of the test is low(< 0.01), which means that there is enough evidence that the flow rate is more than 4 gallons per minute (gpm) and thus, the pump should be put into service.

6 0
3 years ago
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