For which values of P and Q does the following equation have infinitely many solutions? 67x+Q=Px+37

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

Answer:

Hello from MrBillDoesMath!

Answer:

P = 67, Q = 37

Discussion:

Let Q = 37 ( the constant term on the right side of the = ) and

let P = 67 ( the coefficient of x on the left side of the = )

Then the equation becomes 67x + 37 = 67x + 37

which is true for infinitely many x

Regards,

MrB

Step-by-step explanation:

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PLEASE HELP ME!!

tatiyna

For
y=ax²+bx+c
the x value of the axis of symmetry is -b/(2a)

so test them

A., -b/(2a)=-(-8)/(2*-2)=8/-4=-2, yep
B. -b/(2a)=-2/(2*1/2)=-2/1=-2, yep
C. -b/(2a)=-(-16)/(2*4)=16/8=2, nope, need -2
D. -b/(2a)=-12/(2*3)=-12/6=-2, yep

answer is C

3 0

3 years ago

4. Denise thinks of a number, multiplies by 7, and then subtracts 2 from the 5 points

Marta_Voda [28]

Answer:

(<em>t</em> x 7) 5 - 2

Step-by-step explanation:

I think that is how it would look, I hope it helps!

8 0

3 years ago

Question 1(Multiple Choice Worth 1 points)

Stolb23 [73]

so, they already used 4,885.78 this month, but whatever all five family members can use total for a month is 7,250.50, so since they already used 4,885.78, they have left 7,250.50 - 4,885.78 = 2364.72.

$\bf \begin{array}{lllllll} \textit{amount all five}&&\textit{amount they}&\textit{must be}&\textit{amount allowed}\\ \textit{members can use}&&\textit{already used}&\textit{equals or less}&\textit{per month}\\\\ 5x&+&4,885.78&\leqslant&7,250.50 \end{array}$