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3 years ago

What measures air pressure?

Physics

1 answer:

Brums [2.3K]3 years ago

7 0

Answer: barometer

Explanation: An instrument that measures air pressure is called a barometer. One of the first barometers was developed in the 1600s. The original instrument had mercury in the small basin, with an upside down glass tube placed in the mercury.

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A block is released from the top of a frictionless incline plane as pictured above. If the total distance travelled by the block

kotegsom [21]

Complete Question

The diagram for this question is showed on the first uploaded image (reference homework solutions )

Answer:

The velocity at the bottom is $v = 11.76 \ m/ s$

Explanation:

From the question we are told that

The total distance traveled is $d = 1.2 \ m$

The mass of the block is $m_b = 0.3 \ kg$

The height of the block from the ground is h = 0.60 m

According the law of energy

$PE = KE$

Where PE is the potential energy which is mathematically represented as

$PE = m * g * h$

substituting values

$PE = 3 * 9.8 * 0.60$

$PE = 17.64 \ J$

KE is the kinetic energy at the bottom which is mathematically represented as

$KE = \frac{1}{2} * m v^2$

$\frac{1}{2} * m* v ^2 = PE$

substituting values

=> $\frac{1}{2} * 3 * v ^2 = 17.64$

=> $v = \sqrt{ \frac{ 17.64}{ 0.5 * 3 } }$

=> $v = 11.76 \ m/ s$

4 0

3 years ago

(a) Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t)

dolphi86 [110]

Answer:

$r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k$

Explanation:

a(t)=20t i+sin(t) j +cos(2t) k

v(t)= $\int\limits^a_b {a(t)} \, dt$

= $(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k$ ---------------eqn 1

given v(0)=i

i= $c_1i+(-1+c_2)j+(0+c_3)k$

$c_1=1$ $c_2=1$ $c_3=0$

from equation 1

V(t)= $(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k$ ----------eqn 2

now r(t)= $\int\limits^a_b {v (t)} \, dt$

$(\frac{10t^3}{3}+t+c_1)i+(-sint+t+c_2)j+(\frac{-cos2t}{4}+c_3)k$

given r(0)=j

0i+1j+ok = $c_1i+c_2j+(\frac{-1}{4}+c_3)k$

$c_1=0$ $c_2=0$ $c_3 = \frac{1}{4}$

$r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k$

8 0

3 years ago

Ok plz answer and tell me how to do it

kirza4 [7]

Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.

4 0

4 years ago

A student wants to draw a model of an atom. Which statement describes how to find the number of neutrons to include in the model

bekas [8.4K]

Pretty sure it would be B

4 0

3 years ago

Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr

Wittaler [7]

Answer:

A. ) K =126. 7 J

B. ) h= 91.1 m.

Explanation:

Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:

$K = \frac{1}{2}*m*v^{2} = \frac{1}{2}*0.142 kg*(42.24m/s)^{2} = 126.7 J (1)$

Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:

$U_{o} = K_{f} = 126. 7 J (2)$

⇒ m*g*h = 126. 7 J

Solving for h, we get:

$h = \frac{K_{f}}{m*g} = \frac{126.7J}{0.1420kg*9.8m/s2} = 91.1 m (3)$

4 0

3 years ago