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Liula [17]
2 years ago
9

What do car manufacturers do to reduce the fluid friction acting on a car

Physics
2 answers:
Strike441 [17]2 years ago
5 0

Answer:

The fluid friction or drag can be reduced are minimised by giving special shape called streamlined shape to the objects which Move through fluids like air or water

Ivanshal [37]2 years ago
3 0

Answer:

ggggggggggggggggggggggggg

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Which<br> factors will increase the speed of a sound wave in the air?
Dafna11 [192]
A higher temperature, stiffer materials, and less dense materials increase the speed of sound.
7 0
3 years ago
Which sentences describe central ideas of the video? Select all that apply.
sertanlavr [38]

Answer:

the correct answer is see.

Explanation:

it  is wat it isssssssssss

4 0
2 years ago
The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star
Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

PV=nRT

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

V is the volume of a sphere

V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3

V=8.86*10^{50}L

and for n

n=\frac{(4000M_s)/(2*mH)}{6.022*10^{23}mol^{-1}}=3.95*10^{36}mol

Hence, we have (1 Pa = 9.85*10^{-9}atm)

T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K

hope this helps!!

8 0
2 years ago
Avery likes to walk 30 feet in 10<br>seconds. What is her speed?​
Sliva [168]

Answer:

If she is walking 30 feet every 10 seconds, that means she is walking 180 feet per minute. Multiply that by the 60 minutes in an hour, means she walks (180x60)= 10,800 feet an hour.

She walks 3 feet a second.

She walks 180 feet a minute.

She walks 10,800 feet an hour.

Explanation:

6 0
3 years ago
A small 1.0 kg steel ball rolls west at 3.0 m/s collides with a large 3.0 kg ball at rest. After the collision, the small ball m
77julia77 [94]

Answer:

The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

Explanation:

Given that,

Mass of large ball = 3.0 kg

Mass of steel ball = 1.0 kg

Velocity = 3.0 kg

After collision,

Velocity = 2.0 m/s

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

3.0\times0+1.0\times(3.0)(-i)=1.0\times2(-j)+3.0\times v_{2}

-3i+2j=3.0\times v_{2}

v_{2}=-i+0.66j

The direction of the momentum

tan\theta=\dfrac{0.66}{-1}

\theta=tan^{-1}\dfrac{0.66}{-1}

\theta=-33.42^{\circ}

The direction of the momentum with respect to east

\theta=180-33.42=146.58^{\circ}

Hence, The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

7 0
3 years ago
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