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malfutka [58]
4 years ago
11

Jung arrived at a concert in the park do late that the only seat she could get was almost a block from the stage. she could hear

the drums and the bass guitar fairly well but she had trouble hearing higher sounds from the singer .explain the properties and behavior of waves that affected how Jung heard the music.
Physics
2 answers:
stira [4]4 years ago
5 0
The sound waves are going at a different frequency from how far she is but without know how far she is from the stage you cant fix the sound without having to go to the front of the stage.
mario62 [17]4 years ago
3 0
That is the answer of sound waves
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The four stages of listening include hearing, understanding, ________, and responding.
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3 years ago
A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simp
masha68 [24]

To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

T = 2\pi \sqrt{\frac{l}{g}}

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L = g (\frac{T}{2\pi})^2

Our values are given as

g = 9.81m/s

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Replacing,

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5 0
3 years ago
How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h
tresset_1 [31]

Answer:

The  time taken is  t =  32.5 \  s

Explanation:

From the question we are told that

   The  speed  of  first car is  v_1  =  66.7 \ km/h  =  18.3 \  m/s

    The  speed  of  second car is v_2  =  52.7 \ km/h  =  14.64 \  m/s

   The  initial distance of separation is  d =  119 \ m

The distance covered by first car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  0 m/s

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_1 * t

So

     d_t =  0 \  m/s  +  (v_1 * t )

     d_t =  0 \  m/s  +  (18.3 * t )

The distance covered by second  car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  119 m

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_2* t

       d_t =  119  + 14.64 *  t

Given that the two car are now in the same position we have that

    119  + 14.64 *  t  =   0   +  (18.3 * t )

   t =  32.5 \  s

6 0
3 years ago
A trait of an organism that helps it survive in its environment is calles
kompoz [17]
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7 0
3 years ago
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What is the density of a piece of wood with a mass of 25 kg<br> and a volume of 0.0385 m³?
Orlov [11]

Answer:

649kg/m^3

Explanation:

Let p be the density of this particular object.

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p =  \frac{mass \: (in \: kg)}{volume \: (in \:  {m}^{3}) }

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p =  \frac{25kg}{0.0385 {m}^{3} }  \\  = 649kg \: per \:  {m}^{3}

Therefore the density of this object is 649kg/m^3.

7 0
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