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3 years ago

Which best compares freezing and condensation?

2 answers:

4 0

Condensation is a change of state from vapour to liquid while freezing is also a change of state, from liquid to solid. Both are change of states.

Additionally, condensation requires much more energy to change the state of vapor to liquid than it does it change the state of liquid to solid.

Ipatiy [6.2K]3 years ago

4 0

Answer:

C. Both involve the release of heat.

Explanation:

The change in state from liquid to solid (freezing) changes to a state of matter where atoms slow down. This also happens in the change in state from gas to liquid (condensation). The change in this movement is released as heat.

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What is the terminal velocity of blood? A. 8.9 feet/seconds B. 9.8 feet/seconds C. 25.1 feet/second D. 52.1 feet/seconds

goblinko [34]

Answer:

the answer is c) 25.1 feet/second

Explanation:

because the blood droplets can not increase speed past terminal velocity 100.

3 0

3 years ago

A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° n

olchik [2.2K]

Answer:

If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.

F(1x)=F(1)=10 N

F(2x)=F(2)cos60=5•0.5=2.5 N

F(2y) =F(2)sin60 = 5•0.866= 4.33 N

F(3x) =- F(x)=- (10+2.5 )= -12.5 N

F(3y) =- F(2y)= - 4.33 N

F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N

tan φ = F(3y)/F(3x) =4.33/12.5=0.364

φ = 19.1⁰ (south-west)

Explanation:

7 0

3 years ago

Question 26 Unsaved

vlabodo [156]

The density increases

7 0

3 years ago

Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball

Mice21 [21]

The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

$\theta f = 26.3 \deg$
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35

<h3>What is Collison equilibrium?</h3>

According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.

Generally, the equation for Collison equilibrium is mathematically given as

For horizontal motion

mvAx+m2vAx = 2mvfx

For vertical motion

-mvAy+m2vAy = 2mvfy

vfy = 1/2 vAy

$\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\$

$\theta f = 26.3 \deg$

(b)

$v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\$

vf/vA= 0.94

(c)

$Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}$

2vf^2 / 5vA^2 = 0.35

In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

$\theta f = 26.3 \deg$

vf/vA= 0.94

2vf^2 / 5vA^2 = 0.35

Read more about collision theory

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8 0

2 years ago

An object travels back and forth along a straight line. its velocity, in centimeters per second, is given by the function v(t) =

algol13

The correct option for the maximum velocity of the object is the option

13 cm/s.

<h3>What are Functions?</h3>

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.

The reason for the selection is as follows:

The known parameters of the motion of the vehicle are:

The type motion of the vehicle = Repetitive back and forth

The path of the motion of the object = Along a straight line

The function that gives the velocity in centimeters per second (cm/s) is given as follows;

v(t) = 13. sin(π/45 . t)

Where;

t = The time in seconds (a set of the input variables of the function)

v(t) = The velocity of the object (the output variables of the function)

The maximum output value of the sine function = 1, therefore;

sin(π/45 . t) = 1

The units of the of the function is cm/s

Therefore, the maximum velocity of the object is 13 cm/s

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8 0

2 years ago