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asambeis [7]
3 years ago
14

Which best compares freezing and condensation?

Physics
2 answers:
bearhunter [10]3 years ago
4 0

 

Condensation is a change of state from vapour to liquid while freezing is also a change of state, from liquid to solid. Both are change of states.

Additionally, condensation requires much more energy to change the state of vapor to liquid than it does it change the state of liquid to solid.

Ipatiy [6.2K]3 years ago
4 0

Answer:

C. Both involve the release of heat.

Explanation:

The change in state from liquid to solid (freezing) changes to a state of matter where atoms slow down. This also happens in the change in state from gas to liquid (condensation). The change in this movement is released as heat.

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Answer:the 90% is spent performing other functions

Explanation:

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The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of
alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

The capacitance can be expressed in terms of the Area, the permeability constant and the diameter:

C = \frac{\epsilon_0 A}{d}

Where,

\epsilon_0 = Permeability constant

A = Cross-sectional Area

d = Diameter

Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to \rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

Q = CV

Q = \frac{\epsilon A}{d}(Ed)

Q = \epsilon_0 AE

Q = \epsilon_0 \pi(\frac{d}{2})^2E

Q = \frac{\epsilon \pi d^2E}{4}

Re-arranging the equation to find the diameter of the disks, the equation will be:

d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}

Replacing,

d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}

d = 0.0299m

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8 0
3 years ago
If something is a good conductor, what type of insulator is it?
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4. a poor insulator

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8 0
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