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serious [3.7K]
3 years ago
7

A 0.1 kg bouncy ball moves toward a brick wall with a speed of 11 m/s. After colliding with the wall, the ball travels at a spee

d of 8.8 m/s in the OPPOSITE DIRECTION. What is the magnitude of the impulse experience by the ball?
Physics
1 answer:
mr_godi [17]3 years ago
4 0
Impulse is change in momentum.  The initial momentum was
0.1kg*11m/s=1.1kg m/s.
The second momentum is 0.1*(-8.8m/s)=-0.88 (since it's moving backward now)
The difference is P1-P2 = 1.1-(-0.88)=1.98kg m/s
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Answer:

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

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since they tell us that we see the events simultaneously, we can equalize

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We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

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Question is down below
rosijanka [135]

The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

<h3>What are the components of velocity?</h3>

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Learn more about components of velocity:brainly.com/question/14478315

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2 years ago
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azamat

I think it's a.

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