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2 years ago

A glass of root beer with a scoop of ice cream floating on top and a straw sticking out.

Physics

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

These forces are all equal and cancel each other out. Gravity pushes downward on the ice cream. This can also be called the weight of the ice cream. Buoyant force pushes the ice cream upward

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A car traveling at 50 m/s uniformly accelerates to 60 m/s over an 58 second interval. What is the displacement?

yawa3891 [41]

Explanation:

here u = 50m/s

v = 60m/s

t = 58 s

then a = (60-50)/58 m/s2

= 0.17m/s2

now s= ut+1/2at2

so , 50×58+0.5×0.17×(58)^2 m

= 3185.94 m

= 3.18 km

6 0

3 years ago

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Explain how folded mountain ranges form

aleksandrvk [35]

<span>Folded mountains form because two tectonic plates move towards each other at a convergent plate boundary pushing the land up forming a mountain.

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6 0

3 years ago

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How does a nuclear power plant produce energy

nalin [4]

The steam then turns turbines to produce<span> electricity. The difference is that </span>nuclear plants do<span> not burn anything. Instead, they use uranium fuel, consisting of solid ceramic pellets, to </span>produce<span> electricity through a process called fission. best i can do hope it helps</span>

8 0

3 years ago

A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w

son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

$L$ = Inductance = 6 mH

$C$ = Capacitance = 5 μF

$R$ = Resistance = 3 Ω

$\epsilon$ = Maximum emf = 69 V

Resonant angular frequency is given by

$\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz$

The resonant angular frequency is 5773.50269 Hz

Current is given by

$I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A$

The current amplitude at the resonant angular frequency is 23 A

7 0

3 years ago

A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive rea

fgiga [73]

The capacitive reactance is reduced by a factor of 2.

<h3>Calculation:</h3>

We know the capacitive reactance is given as,

$Xc = \frac{1}{2\pi fC}$

where,

$Xc\\$ = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

$Xc$ =?

$Xc' = \frac{1}{2\pi f'C}$

$= \frac{1}{2\pi 2f C}$

$= \frac{1}{2} (\frac{1}{2\pi fC} )\\$

$Xc' = \frac{1}{2} Xc$

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

The capacitive reactance is doubled.
The capacitive reactance is traduced by a factor of 4.
The capacitive reactance remains constant.
The capacitive reactance is quadrupled.
The capacitive reactance is reduced by a factor of 2.

Learn more about capacitive reactance here:

brainly.com/question/23427243

#SPJ4

3 0

2 years ago