Answer:
Took the test, answer is C) 17(100)+17(40)+17(4)
Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have

Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius 
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are



Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a
matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
7/10,.72,75%,4/5,.9 hope this helped
Y=4
3y/4=12/3
y=4 3/3=1
12/3=4 so y=4