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Art [367]
3 years ago
15

Accelerated motion is represented by a _____ line on a nonlinear distance-time graph.

Physics
2 answers:
Natasha_Volkova [10]3 years ago
4 0

Accelerated motion could be changing speed, or changing direction, or both.

If it's only the direction changing and not the speed, then you'll never see it on a distance/time graph.

If the speed is changing, then a <em>velocity</em>/time graph can be any kind of a line except horizontal or vertical, and a <u><em>distance</em></u>/time graph must be <em>curved</em>.

Delicious77 [7]3 years ago
4 0

Answer:

Accelerated motion is represented by a <u>CURVED</u> line on a nonlinear distance-time graph.

Explanation:

For uniform acceleration we know that

\frac{dv}{dt} = a

now integrating both sides we will have

\int dv = \int adt

now after integration we will have

v - v_o = at

now we have

v = v_o + at

again we know that

\frac{dx}{dt} = v_o + at

again by integration both sides

x - x_0 = v_o t + \frac{1}{2}at^2

x = x_0 + v_0t + \frac{1}{2}at^2

now since this equation is a quadratic equation so here distance time graph must be a curved graph

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How many electrons does it take to make up 4.33 C of charge?
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Answer:

Number of electrons, n=2.7\times 10^{19}

Explanation:

It is given that,

Charge, q = 4.33 C

We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :

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n=\dfrac{q}{e}

n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}

n=2.7\times 10^{19}

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The use of a laser beam to seal leaky blood vessels and to prevent the growth of new ones in diabetic retinopathy is called lase
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The use of a laser beam to seal leaky blood vessels and to prevent the growth of new ones in diabetic retinopathy is called laser <u>photocoagulation.</u>

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Una persona cierra una puerta de 1 metro de ancho aplicando una fuerza de 40 [N], perpendicular a ella, a 90 [cm] de su eje de r
Damm [24]

Answer:

El módulo del torque aplicado es 36 Nm

Explanation:

En los movimientos rotatorios, la cantidad de fuerza aplicada no depende de la acción gravitacional sino del momento inercial, que es el equivalente angular de la inercia (masa) y representa la resistencia que un objeto ofrece al rotar alrededor de su eje. Cuando un cuerpo rígido rota alrededor de su eje debe considerarse , además de la masa, el radio de giro ya que estos dos factores determinan la resistencia del cuerpo a los cambios de movimiento rotatorio a través de un eje determinado.

De esta manera, se llama torque o momento de una fuerza a la capacidad de dicha fuerza para producir un giro o rotación alrededor de un punto.

En muchas ocasiones el punto de aplicación de la fuerza no coincide con el punto de aplicación en el cuerpo. En este caso la fuerza actúa sobre el objeto y su estructura a cierta distancia, mediante un  elemento que traslada esa acción de esta fuerza hasta el objeto. Entonces, el momento de una fuerza  es, matemáticamente,  igual al producto de la intensidad de la fuerza (módulo) por la distancia desde el punto de aplicación de la fuerza hasta el eje de giro:

M=F*d*sen θ

donde F es la fuerza en Newton (N), d la distancia en metros (m), θ el ángulo que forma la fuerza con el objeto al cual se le aplica la fuerza y M el momento, que se mide en Newton por metro (Nm).

En este caso:

  • F= 40 N
  • d= 90 cm= 0.9 m (siendo 100 cm= 1 m)
  • θ= 90° ya que la fuerza se aplica de forma perpendicular. Entonces sen θ= sen 90= 1

Reemplazando:

M=40 N*0.9 m* 1

Resolviendo:

M= 36 Nm

<u><em>El módulo del torque aplicado es 36 Nm</em></u>

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