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Art [367]
3 years ago
15

Accelerated motion is represented by a _____ line on a nonlinear distance-time graph.

Physics
2 answers:
Natasha_Volkova [10]3 years ago
4 0

Accelerated motion could be changing speed, or changing direction, or both.

If it's only the direction changing and not the speed, then you'll never see it on a distance/time graph.

If the speed is changing, then a <em>velocity</em>/time graph can be any kind of a line except horizontal or vertical, and a <u><em>distance</em></u>/time graph must be <em>curved</em>.

Delicious77 [7]3 years ago
4 0

Answer:

Accelerated motion is represented by a <u>CURVED</u> line on a nonlinear distance-time graph.

Explanation:

For uniform acceleration we know that

\frac{dv}{dt} = a

now integrating both sides we will have

\int dv = \int adt

now after integration we will have

v - v_o = at

now we have

v = v_o + at

again we know that

\frac{dx}{dt} = v_o + at

again by integration both sides

x - x_0 = v_o t + \frac{1}{2}at^2

x = x_0 + v_0t + \frac{1}{2}at^2

now since this equation is a quadratic equation so here distance time graph must be a curved graph

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Olegator [25]

Answer:

1) Addition of a catalyst

2) To change the reaction rate of slope B to look like slope A, simply add a catalyst to speed up the rate of reaction, giving you a higher amount of products in a shorter amount of time (line A)

Explanation:

1 and 2)Two things can alter the rate of a reaction, either the addition of a catylist which will not alter the composition of the products or reactants, but will accelerate the reaction time, or an increase in temperature will also increase the rate at which a reaction will occur.

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2 years ago
Which are base units used in the metric system? Check all that apply.
Shtirlitz [24]

Liters

Grams

Degrees Celsius

The other answer choices are from the imperial system

7 0
3 years ago
Read 2 more answers
If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
Ymorist [56]
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
7 0
3 years ago
The ground state energy of an oscillating electron is 1.23 eV. How much energy must be added to the electron to move it to the t
Vikki [24]

Answer:

  • The energy that must be added to the electron to move it to the third excited state is  -1.153 eV
  • The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

Explanation:

Given;

Energy of electron in ground state (n = 1 ) = 1.23 eV

E₁ = 1.23 eV

Eₙ = E₁ /n²

where;

E₁ is the energy of the electron in ground state

n is the energy level,

For third excited state, n = 4

E₄ = E₁ /4²

E₄ = (1.23 eV) / 16

E₄ = 0.077 eV

Change in energy level, = E₄ - E₁ = 0.077 eV - 1.23 eV = -1.153 eV

The energy that must be added to the electron to move it to the third excited state is  -1.153 eV

For fourth excited state, n = 5

E₅ = E₁ /5²

E₄ = (1.23 eV) / 25

E₄ = 0.049 eV

Change in energy level, = E₅ - E₁ = 0.049 eV - 1.23 eV = -1.181 eV

The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

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This is true!!

Good luck hope this helped!
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