Si velocidad es de 5m/s y esta recorriendo un parke de un tamaño de 7.2 kilometros, su recorrido le duro 1 hora y 44 minutos.
Dividi los kilómetros del parque por la velocidad, dándomela la hora que duró su recorrido
7.2÷5=1.44
The north and west components of this displacement are 9.19 km and -7.71 km respectively.
<h3>
North component of the displacement</h3>
The north component of the displacement is calculated as follows;
Dy = D sinθ
Dy = 12 km x sin50
Dy = 9.19 km
<h3>West component of the displacement</h3>
Dx = D x cosθ
Dx = - 12 km x cos(50)
Dx = -7.71 km
Learn more about components of displacement here: brainly.com/question/13416288
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Answer:
11.9 minutes
Explanation:
The journey is 5000 meters long. The time it takes in seconds for the journey at this speed is 5000/7 =714 seconds.
714/60=time in minutes =11.9 minutes approximately.
She say give tow points and write the equation of the line with the two give points (1,5) and (-3,-5 )
