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Dmitrij [34]
3 years ago
9

PLEASE HELPPPPP I WILL GIVE POINTS AND BRAINIEST

Physics
2 answers:
Elza [17]3 years ago
5 0
I agree^ fjidnsnwjskocucuhrebnaosicuej
UNO [17]3 years ago
3 0

Answer:

Graph A

Explanation:

I hope this is right

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In which of the following cases is the torque about the shoulder due to the weight of the arm the greatest? Case 1: A person hol
Alexeev081 [22]

Answer: a) Case 2 b) Case 1

Explanation:

a) By definition, the magnitude of a torque, referred to a given point, is expressed as the product of the force that causes the torque, times the perpendicular distance to the reference point.

If we assume that the only force acting on the arm is the weight of the arm, and that this is concentrated in a point in the center of it (taking the arm as a solid bar with the center of mass at the mid-point), clearly the torque will be the greatest when the force be exactly perpendicular, which is the case of the arm placed straight out parallel to the ground (Case 2).

b)  As the torque and the angular acceleration are directly proportional each other (being the rotational inertia the proportionality constant) the angular acceleration will be maximum when torque be maximum also, which is the case that the arm begins to swim, due to the perpendicular distance to the shoulder is the maximum possible (Case 1).

6 0
3 years ago
A motor does a total of 480 joules of work in 5.0 seconds to lift a 12-kilogram block to the top of a rampThe average power deve
Flauer [41]

Answer:

there it is fella

we neglect the mass data

3 0
3 years ago
How are speed and velocity different?
liubo4ka [24]

Velocity tells you how fast and in what direction. Speed only tells how fast.

4 0
3 years ago
Read 2 more answers
Need help with this science!!
noname [10]
Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).
3 0
3 years ago
A biconvex lens is formed by using a piece of plastic(n=1.70).
creativ13 [48]

Answer:

f =17.15\ cm

Explanation:

given,

refractive index of lens, n = 1.70

Radius of curvature of front surface. R₁ = 20 cm

Radius of curvature of the back surface, R₂ = 30 cm

focal length= ?

\dfrac{1}{f}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})

    R₁ = +20 cm

    R₂ = -30 cm

    n = 1.70

\dfrac{1}{f}=(1.70-1)(\dfrac{1}{20}-\dfrac{1}{-30})

\dfrac{1}{f}=0.70 \times 0.0833

f = \dfrac{1}{0.7 \times 0.0833}

f =17.15\ cm

the focal length of the lens is equal to 17.15 cm

3 0
3 years ago
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