1. To solve this question, you need to equalize the mass of solute for both solution. The calculation would be:
mass of solute= volume*concentration
mass1=mass2
volume1 * concentration1 = volume2 * concentration2
volume1 * 0.7%= 2L *(1000ml/L) * 0.2%
volume1 = 2000ml * (0.2%/0.7%)
volume1= 571.429 ml
2. Since you already have the volume of stock needed, you just need to subtract it from the total solution volume to count the number of solvents needed.
new solution volume= stock volume + diluting solvent volume
2L * 2000ml/L = 571.429ml + diluting solvent volume
diluting solvent volume= 2000ml- 571.429 ml= 1428.571ml
Answer:
I’m not sure probably false
Explanation:
Take 36 / (24 + 6 + 32) = 0.580 mol
0.580/.175 = 3.31 m
depression = 1.86 * 3.31 = 6.16
Subtract from 0 gives -6.16 C closest is A
Answer:
1. Ionic solids dissolve in water.
2. Ionic solid is a better conductor compared to covalent solid.
Explanation:
1. Ionic solids dissolves in water because the water molecules hydrate the ions.When ionic compounds dissolve in water, they break apart into the ions that make them up through a process called dissociation.
Whereas covalent solids don't dissolve in water, instead making a separate layer on the water's surface.
For example table salt that is NaCl is an ionic solid.When we add the salt in water it completely dissolves in water and disappears on the other hand oil is a covalent solid, when we add it in water it does not dissolve and forms a layer on water surface.
2.Ionic solids conducts electricity when it dissolves in water. Because in aqueous form there are ions which conducts electricity.
But covalent solids does not conduct in any form neither in pure form nor in aqueous form because they are bond with shared electrons having no ions which conducts electricity.
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)
So, according to the balanced equation of the reaction:
and by using ICE table:
Ag2CrO4(s) → 2Ag+ (Aq) + CrO4^2-(aq)
initial 0 0
change +2X +X
Equ 2X X
∴ Ksp = [Ag+]^2[CrO42-]
so by substitution:
∴ 3.83 x 10^-11 = (2X)^2* X
3.83 x 10^-11 = 4 X^3
∴X = 2.1 x 10^-4
∴[CrO42-] = X = 2.1 x 10^-4 M
[Ag+] = 2X = 2 * (2.1 x 10^-4)
= 4.2 x 10^-4 M
when we comparing with the actual concentration of [Ag+] and [CrO42-]
when moles Ag+ = molarity * volume
= 0.004 m * 0.005L
= 2 x 10^-5 moles
[Ag+] = moles / total volume
= 2 x 10^-5 / 0.01L
= 0.002 M
moles CrO42- = molarity * volume
= 0.0024 m * 0.005 L
= 1.2 x 10^-5 mol
∴[CrO42-] = moles / total volume
= (1.2 x 10^-5)mol / 0.01 L
= 0.0012 M
by comparing this values with the max concentration that is saturation in the solution
and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.
∴ the excess will precipitate out
