Why do people remove entire forests ?

Why does electronegativity decrease from right to left within a period?

Firlakuza [10]

Explanation:

so, as you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus. electronegativity increases as you move from left to right across a period on the periodic table.

4 0

3 years ago

At constant temperature, if a gas occupies 312 mL at a pressure of 1.60 atm, what pressure is necessary for this gas to occupy a

inn [45]

Answer:

P₂ = 1.0 atm

Explanation:

Boyles Law problem => P ∝ 1/V at constant temperature (T).

Empirical equation

P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂

Given

P₁ = 1.6 atm

V₁ = 312 ml

P₂ = ?

V₂ = 500 ml

P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm

5 0

3 years ago

The elemental mass percent composition of ascorbic acid (vitamin C ) is 40.92% C , 4.58% H , and 54.50% O . Determine the empiri

Lady bird [3.3K]

The empirical formula of ascorbic acid is C6H8O6.

<h3>Empirical formula</h3>

To calculate the empirical mass of a compound from the mass percentage of each element, the value of the molar mass of each element is used, which in this case corresponds to:

$MM_C= 12g/mol\\MM_H=1g/mol\\MM_O=16g/mol$

From this, we consider that the compound has 100 grams, so the number of moles of each element will be equal to:

$C = \frac{40.92}{12} = 3.41 \\H = \frac{4.58}{1}=4.58\\ O =\frac{54.50}{16}=3.41$

Now, divide all the values found by the smallest value, to find the amount present in each element:

$C = \frac{3.41}{3.41} = 1\\ H = \frac{4.58}{3.41} = 1.34\\O = \frac{3.41}{3.41} = 1$

As you can see, the value of moles of hydrogen resulted in a decimal number, so it is necessary to multiply all values by a number in common until the three meet as integers:

$C = 1 \times 6 = 6\\H = 1.34 \times 6 = 8\\O = 6 \times 6 = 6$

So, the empirical formula of ascorbic acid is C6H8O6.

Learn more about empirical and molecular formula in: brainly.com/question/11588623

7 0

3 years ago

Where do the OH- ions go as additional acid is added?

qwelly [4]

The result when the OH- ions go as additional acid is added is that they remain in solution but change concentration. This is because when you add more acid to hydroxide, it will change its concentration due to the acidity added.

8 0

3 years ago

Read 2 more answers

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

Anna [14]

Answer: The number of moles of ethanol after equilibrium is reached the second time is 11. moles.

Explanation:

We are given:

Initial moles of ethene = 34 moles

Initial moles of water vapor = 15 moles

The chemical equation for the formation of ethanol follows:

$CH_2=CH_2+H_2O\rightleftharpoons CH_3CH_2OH$

Initial: 34 15

At eqllm: 34-x 15-x x

We are given:

Equilibrium moles of ethene = 24 moles

Equilibrium moles of water vapor = 5 moles

Calculating for 'x'. we get:

$34-x=24\\\\x=10$

Volume of container = 100.0 L

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CH_3CH_2OH]}{[CH_2=CH_2][H_2O]}$ .......(1)

$[CH_3CH_2OH]=\frac{10}{100}=0.1M$

$[CH_2=CH_2]=\frac{24}{100}=0.24M$

$[H_2O]=\frac{5}{100}=0.05M$

Putting values in expression 1, we get:

$K_c=\frac{0.1}{0.24\times 0.05}\\\\K_c=8.3$

Now, 11 moles of ethene gas is again added and equilibrium is re-established, we get:

The chemical equation for the formation of ethanol follows:

$CH_2=CH_2+H_2O\rightleftharpoons CH_3CH_2OH$

Initial: 24+11 5 10

At eqllm: 35-x 5-x 10+x

$[CH_3CH_2OH]=\frac{10+x}{100}$

$[CH_2=CH_2]=\frac{35-x}{100}$

$[H_2O]=\frac{5-x}{100}$

Putting values of in expression 1, we get:

$8.3=\frac{\frac{(10+x)}{100}}{\frac{(35-x)}{100}\times \frac{(5-x)}{100}}\\\\8.3=\frac{(10+x)\times 100}{(35-x)\times (5-x)}\\\\x^2-52x+55=0\\\\x=50.9,1.1$

The value of 'x' cannot exceed '35', so the numerical value of x = 50.9 is neglected.

Moles of ethanol = $(10+x)=10+1.1=11.$

Hence, the number of moles of ethanol after equilibrium is reached the second time is 11. moles.

8 0

3 years ago