Question

Need urgent help with easy math. Simplify the expression below.

Answer 1

Answer:

A

Step-by-step explanation:

Factorise the numerator and denominator

w² - 9 = (w - 3)(w + 3) ← difference of squares

w² - 4w - 21 = (w - 7)(w + 3)

Hence the expression can be expressed as

$\frac{(w-3)(w+3)}{(w-7)(w+3)}$

Cancel the factor (w + 3) on the numerator/denominator. leaving

$\frac{w-3}{w-7}$ → A

Answer 2

Answer:A

Step-by-step explanation:

w² - 9 = (w - 3)(w + 3) ← difference of squares

w² - 4w - 21 = (w - 7)(w + 3)

Hence the expression can be expressed as

\frac{(w-3)(w+3)}{(w-7)(w+3)}

Cancel the factor (w + 3) on the numerator/denominator. leaving

\frac{w-3}{w-7} =A

I hope l can help you :)