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2 years ago

How do I find the answer for 25/8-6/8

2 answers:

4 0

First, subtract the numerators and keep the denominator. so it will be 19/8 then turn into a mixed number which will be 16 1/4

MAXImum [283]2 years ago

4 0

So 2 and 5/8 equals 21/8. Whenever you turn a mixed number into an improper fraction, multiply the whole number by the denominator and add the numerator. Since both fractions already have a common denominator, all you need to do is subtract the numerators and don't touch the denominator.

21/8 - 6/8 = 15/8 = 1 7/8

This cannot be simplified any further so I would write it as a mixed fraction.

Hope this helps!

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Rhett made $250 washing cars with his mobile car wash company. He charges $70 per car and earned $50 in tips. Write an equation

Vadim26 [7]

Answer: 250=70x+50

Step-by-step explanation:

250 being the total would go at the equal sign

250=

And since it says 70 Per car that means it would be 70x so

250=70x

50 dollars in tips is a total so

250=70x+50 is your equation

3 0

3 years ago

Read 2 more answers

18. QS bisects ZPQR. If mZPQS = 3x and

il63 [147K]

The answer is b because

6 0

2 years ago

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

4 0

2 years ago

If point (7.b) is in Quadrant I and point (a.--3)

lys-0071 [83]

The point (a,b) would be in quadrant 2 (the one on the top left)

6 0

2 years ago

Read 2 more answers

2x+4y=24 -12x+8y=-16

EleoNora [17]

Dividing the first equation by 2
X + 2y = 12
Dividing the equation 2 by 4
-3x + 2y = -4
subtracting both equations
4x = 16
X = 4
Also 4 + 2y = 12
2y = 8
Y = 4
Please mark as brainliest

3 0

2 years ago