Answer:
The solution is:
Step-by-step explanation:
Considering the expression










Solving the right side of the equation A.

As

Because


⇒ 


So





So, equation A becomes






Therefore, the solution is
3/3-1/3= 2/3 of the glasses
Answer:
yes
Step-by-step explanation:
Answer:
Strength and direction of the relationship.
Step-by-step explanation:
Given that A study finds a correlation coefficient of r = .32. This number gives you information about which of the following?
Group of answer choices Type of relationship and importance Statistical validity and external validity Statistical significance and effect size Strength and direction of the relationship.
We know that correlation coefficient represented by r is a measure of association between two variables. r can lie between -1 and 1. While negative correlation suggests inverse relationship positive a positive association.
0 correlation means the two variables are independent.
If nearer to 0, it represents weak correlation and nearer to 1 than 0 represents strong correlation.
Here r =0.32 a weak positive correlation
r represents
Strength and direction of the relationship.
Answer:
A. 20,000 square feet
Step-by-step explanation:
The description is that of a rectangle 200 ft long and 100 ft wide. The area is the product of those dimensions:
area = (200 ft)(100 ft) = 20,000 ft²