Answer:
The correct option is c) a loss of $8.
Step-by-step explanation:
Consider the provided information.
If the selling price of two item is same and one item sold at a profit of x % and other at a loss of x % in that case total sale result loss:
To calculate the loss use the formula: ![Loss\ \%=(\frac{x}{10})^2\ \%](https://tex.z-dn.net/?f=Loss%5C%20%5C%25%3D%28%5Cfrac%7Bx%7D%7B10%7D%29%5E2%5C%20%5C%25)
It is given that he had a profit of 20 percent on the sale of one of the shares but a loss of 20 percent on the sale of the other share, where the selling price is $96 each.
That means the total sale result will be a loss.
Now use the above formula by substitute x=20.
![Loss\ \%=(\frac{20}{10})^2\ \%\\\\Loss\ \%=4\ \%](https://tex.z-dn.net/?f=Loss%5C%20%5C%25%3D%28%5Cfrac%7B20%7D%7B10%7D%29%5E2%5C%20%5C%25%5C%5C%5C%5CLoss%5C%20%5C%25%3D4%5C%20%5C%25)
It is given that the sales price is $96 of each that means total sales price is:
$96+$96=$192
Let the cost price of the shares were x.
According to question: x-4% of x = 192
![x-\frac{4}{100}\times x = 192\\\\x-0.04x = 192\\\\0.96x = 192\\x = 200](https://tex.z-dn.net/?f=x-%5Cfrac%7B4%7D%7B100%7D%5Ctimes%20x%20%3D%20192%5C%5C%5C%5Cx-0.04x%20%3D%20192%5C%5C%5C%5C0.96x%20%3D%20192%5C%5Cx%20%3D%20200)
Hence, the cost price of the shares was 200.
Loss = Cost price -Sales price
Loss = $200 - $192
Loss = $8
Hence, the correct option is c) a loss of $8.