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elixir [45]
2 years ago
12

If the titrant has a molarity of 0.1000 m and there are 45.00 ml of analyte present, what is the molarity of the analyte?

Chemistry
1 answer:
marysya [2.9K]2 years ago
4 0
Given: 

Concentration of titrant = 0.1000 M
Volume of titrant = 45 mL

The molarity of analyte depends on the amount of the analyte present in the titrated solution. If the amount of analyte is 20 mL, then its concentration is:

45ml * 0.10 M = C analyte * 20 ml

C analyte = 0.225 M
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How many grams are in 2.3 x 10^-4 moles of Ca3(PO4)2
OLEGan [10]
Molar mass 

Ca₃(PO₄)₂ = 310 g/mol

1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?

m = 2.3x10⁻⁴ * 310 / 1

m = 0.0713 g 

hope this helps!
3 0
3 years ago
Which of the following is a nonpolar molecule?
mylen [45]

<u>Answer:</u> The correct option is A) a nitrogen molecule.

<u>Explanation:</u>

Polar covalent molecules are defined as chemical compounds in which the difference in electronegativity between the atoms is not equal to 0. These molecules are formed by heteronuclear molecules.

Heteronuclear molecules are defined as the molecules which are formed by the combination of more than one type of atom having a different nucleus.

Non-polar covalent molecules are defined as chemical compounds in which the difference in electronegativity between the atoms is equal to 0. These molecules are formed by homonuclear molecules.

Homonuclear molecules are defined as the molecules which are formed by the combination of one type of atom having the same nucleus.

From the given options:

  • A) A nitrogen molecule

It is a homonuclear molecule formed by the combination of 2 nitrogen atoms

  • B) A nitrogen monoxide molecule

It is a heteronuclear molecule formed by the combination of 1 nitrogen and 1 oxygen atoms

  • C) A linear nitrogen oxide molecule (N_2O) with nitrogen in the center

It is a heteronuclear molecule formed by the combination of 2 nitrogen and 1 oxygen atom and has some dipole moment. Thus, is considered a polar molecule

  • D) A bent nitrogen dioxide molecule (NO_2) with nitrogen in the center

It is a heteronuclear molecule formed by the combination of 1 nitrogen and 2 oxygen atoms and has some dipole moment. Thus, is considered a polar molecule

Hence, the correct option is A) a nitrogen molecule.

6 0
2 years ago
point Deshawn ran the 400 m race(in a straight line) in 2 minutes. What is his distance and displacement ? Explain your answer b
san4es73 [151]

His distance and displacement are the same, which was 400 m

<h3>Further explanation</h3>

Given

Distance = 400 m

time = 2 min

Required

Distance and displacement

Solution

Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude  

Can be simplified distance = totals traveled  

Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction  

Can be simplified displacement = distanced traveled from starting point to ending point  

From the definition above shows that the displacement and the distance that he traveled have the same value (magnitude), which is equal to 400 m

The value of the two will be different if he starts and finishes at the same point, then the displacement value is zero while the distance he has traveled is still 0

4 0
2 years ago
If an atom has 34 protons and 40 neutrons, what is its mass number? 40 6 74 34
Darya [45]
Protons+Neutrons
34+40= 74
7 0
3 years ago
Read 2 more answers
During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

7 0
2 years ago
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