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kow [346]
3 years ago
10

Write and balance an equation for the following reaction. Identify the type of reaction.

Chemistry
1 answer:
Strike441 [17]3 years ago
8 0

Answer: Synthesis/ Combination

reaction

4 Al + 3S2 => 2 Al2S3

Explanation: The equation is now balanced the amount of each individual atom in both the reactant and product sides are equal.

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When 100ml of M HCl is mixed with 100ml of N NaOH, the pH of the resulting solution is
RoseWind [281]

Answer:

Option d. 7

Explanation:

A mixture of a strong base and a strong acid produce a neutral salt and water.

This is the reaction of neutralization:

HCl + NaOH → NaCl + H₂O

NaCl →  Na⁺  +  Cl⁻

Sodium chloride is neutral salt which does not give H⁻ neither OH⁻ to medium, that's why pH is neutral.

Both ions are derivated from a strong acid and base so they do not make hydrolisis. They are a conjugate pair of a weak acid and base. The reactions can not occur:

Cl⁻  +  H₂O ← OH⁻  +  HCl

Na⁺  +  H₃O⁺ ← NaOH  + H₂O

4 0
3 years ago
Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 Pa at a temperature of 127 C.
Phoenix [80]

Hey there!


* Converts 1750 dm³ in liters :


1 dm³ = 1 L so 1750 dm³ = 1750 liters



* Convertes 125,000 Pa in atm :


1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm


* Convertes 127ºC in K :


127 + 273.15 => 400.15 K


R = 0.082 atm.L/mol.K


Finally, it uses an equation of clapeyron :


p * V = n * R * T


1.233 * 1750 = n * 0.082 * 400.15


2157.75 = n * 32.8123


n = 2157.75 / 32.8123


n = 65.76 moles



hope this helps!



5 0
3 years ago
Read 2 more answers
10.0 grams of water are heated during the preparation of a cup of coffee 1.0x 103 j of the heat are added to the water. which is
katovenus [111]

<u>Answer:</u> The final temperature of the coffee is 43.9°C

<u>Explanation:</u>

To calculate the final temperature, we use the equation:

q=mC(T_2-T_1)

where,

q = heat released = 1.0\times 10^3J=1000J

m = mass of water = 10.0 grams

C = specific heat capacity of water = 4.184 J/g°C

T_2 = final temperature = ?

T_1 = initial temperature = 20°C

Putting values in above equation, we get:

1000J=10.0g\times 4.184J/g^oC\times (T_2-20)\\\\T_2=43.9^oC

Hence, the final temperature of the coffee is 43.9°C

6 0
3 years ago
3 examples of potential energy
spin [16.1K]
The potential energy .. 
1- when a rubber band is stretche and waiting to be released 
2- an acorn hanging from a oak tree
3- a pice of celery 

4 0
3 years ago
Please help me I really don’t understand
Leokris [45]
I dont understand life, for example, look at my username.

4 0
3 years ago
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