Given mass of solute = 340 gram
Molar mass of solute(MgBr2) = 184 g
Number of moles = Given mass / Molar mass = 340 / 184 = 1.85 moles
Now, Molarity = Number of moles / solution (in litres)
So, M = 1.85 / 8
M = 0.23 M
In short, Your Molarity would be: 0.23 M
Hope this helps!
One mole of Na2SO4 is 6.022 * 10^(23) molecules. We can divide this into the quantity in the question to find a value of 1.5/6.022 = 0.2491 moles. Rounded to two significant figures and put in scientific notation, we can rewrite this quantity as 2.5 * 10^(-1) moles
Answer:
Explanation:
K₂CrO₄ + ( COONa )₂ + 2BaCl₂ = Ba CrO₄ + ( COO ) ₂ Ba + 2 KCl + 2 NaCl
.033 M .053 M
Ksp of Ba CrO₄ is 2.10×10⁻¹⁰
Ksp of ( COO ) ₂ Ba is 1.30×10⁻⁶
A ) Ksp of Ba CrO₄ is less so it will precipitate out first .
B) Ksp = 2.10×10⁻¹⁰
Ba CrO₄ = Ba⁺² + CrO₄⁻²
C .033
C x .033 = 2.10×10⁻¹⁰
C = 63.63 x 10⁻¹⁰ M
Ba⁺² must be present in concentration = 63.63 x 10⁻¹⁰ M
C)
90% of precipitation of barium oxalate
concentration of oxalate to precipitate out = .9 x .0532 = .04788
( COO ) ₂ Ba = (COO)₂⁻² + Ba⁺²
.04788 M C
C x .04788 = 1.30×10⁻⁶
C = 27.15 x 10⁻⁶ M .
They are different substances because in the weight and size, they are different.
in weight gas weighs nothing but every solid is different.
same with liquids.
Answer:
The answer to your question is π = 12.47 atm
Explanation:
Data
mass of Magnesium citrate = 25.5 g
volume of solution = 244 ml
temperature = 37°C
molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g
Osmotic pressure = π = ?
Process
1.- Calculate the moles of magnesium citrate
214 grams ----------------- 1 mol
25.5 grams --------------- x
x = (25.5 x 1)/214
x = 0.119
2.- Calculate molarity
Molarity = moles/volume
Molarity = 0.119/0.244
Molarity = 0.49
3.- Calculate osmotic pressure
π = MRT
π = (0.49)(0.0821)(37 + 273)
π = (0.49)(0.0821)(310)
π = 12.47 atm
