The mass of ethanol is consumed by the reaction of 3.37g oxygen gas is 4.85g
Explanation:
The balanced equation for the chemical reactions is;
CH₃CH₂OH + O₂ → CH₃COOH + H₂O
The mole ratio between oxygen and ethanol in the reaction is 1 : 1
The molar mass of O₂ is 32g / mole. Therefore the O₂ moles consumes in the reaction is;
3.37 / 32
If the molar mass of ethanol is 46.07g/mole, and the ration of reaction in 1 : 1; Then the moles of ethanol consumed is;
3.37/32 * 46.07
= 4.85g
Answer:
a. 174 mL
Explanation:
Let's consider the following reaction.
2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)
We have 155.0 mL of a 0.112 M lead(II) nitrate solution. The moles of Pb(NO₃)₂ are:
0.1550 L × 0.112 mol/L = 0.0174 mol
The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:
2 × 0.0174 mol = 0.0348 mol
The volume of a 0.200 M KI solution that contains 0.0348 moles is:
0.0348 mol × (1 L / 0.200 mol) = 0.174 L = 174 mL
