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diamong [38]
3 years ago
11

The orbits of ___ lie closer to the Sun than does Earth's orbit.

Chemistry
1 answer:
vampirchik [111]3 years ago
8 0
Mercury and Venus is the correct answer
You might be interested in
What is the frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm?
morpeh [17]

The frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm is 5.71×10^{14} s^{-1}

What is wavelength?

  • It is the length between two successive crests or troughs of any wave.

What is a frequency?

  • It is the total number of waves that pass through a fixed point in unit time.

Wavelength=525nm

The relation between wavelength and frequency

v=\frac{c}{lambda}

v=frequency

c=speed of light = 3.0×10^{8}m/sec

λ(lambda)=wavelength

substitute the value in the equation mentioned above

v=3.0×10^{8}/525×10^{-9}

=5.71×10^{14}s^{-1}

hence, the frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm is 5.71×10^{14} s^{-1}

learn more about hydrogen emission here:

brainly.com/question/27231030

#SPJ10

8 0
2 years ago
The rate of disappearance of HBr in the gas phase reaction 2HBr(
Iteru [2.4K]
The correct answer would be 0.1505 M/s. Given the rate of disapperance of HBr, we can easily calculate the rate of apearance of the products by looking at the coefficients of the substances in the reaction. In this case, for every two moles of HBr, 1 mole of Br2 is being produced so the reaction rate would be:

- 1/2 (r(HBr)) = rBr2
- 1/2 (-0.301) = rBr2
Rate of appearance of Br2 = 0.1505 M/s
3 0
3 years ago
What factors could be used to increase reaction rate? Check all that apply.
ludmilkaskok [199]

The rate of a reaction can be increased by:

-using a catalyst- it lowers the activation energy and leads to less energy required to break bonds of reactants. This lower activation energy leads to more products formed with less time, hence an increase reaction rate.

-increasing temperature- the particles of a molecule move faster and undergo more collision which leads to an increase in the speed of the reaction.

-increasing pressure- means there is more particles of reactants in a reduced volume. The particles do not need to move long distances to find another particle to react with, hence the rate of reaction increases.

Using an inhibitor will not increase the rate of the reaction because, an inhibitor binds to the active site where a catalyst is supposed to act. This means a higher activation energy and thus a decrease in reaction rate.

Likewise, decreasing the concentration implies  few particles available to collide with each other and that slow down the speed of the reaction.

4 0
3 years ago
Read 2 more answers
MARK AS BRAINLIEST IF YOU ANSWER THIS CORRECTLY
Sunny_sXe [5.5K]
C. If the banks of the river are eroding, then the river will be wider.
5 0
3 years ago
On a day wilderness expedition you'll need to heat of water to the boiling point each day. The air temperature will average . Yo
AlladinOne [14]

Answer:

36

Your question is not complere. but maybe it is like:

5 day expedition.

you'll need to heat 4.0kg

Air Temperature: 25 °C

each canister has 75 g

The standar heat of formation of propane at 25°C is −103.85 / kJmol...

If the data is not exactly the same, you can follow the same steps.

Explanation:

Given:

Weight of water = 4.0 kg = 4000 g

Boiling point  = 100 °C (T2)

Initial T ° Water= 25 °C (T1)

Specific heat capacity water (Cs) = 4.184 J / g°C

Then  

Energy (q) = m x Cs x (T2-T1)

q = 4000 g x  4.184 J / g°C x (100-25) °C

q = 1255200 J per day

For 5 days the amount of energy will be 5xq = 6276000 J = 6276 kJ

Then we know that the standard heat of formation of propane at 25°C is −103.85kJ/mol. Also, Molecular Weight propane= 44,1 g / mol

 

Then we can know how much propane it's needed:

Mass= 6276 kJ÷103.85 kJ / mol = 60.43 mol

Mass of propane= 60.43 mol ×  44,1 g/mol = 2664.9 g  

So, if each canister has 75.g of propane:  

Number of canister=  2664.9 g ÷ 75.g = 35.53 = 36 canisters

4 0
2 years ago
Read 2 more answers
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