<h3>
Answer:</h3>
2000 atoms
<h3>
Explanation:</h3>
We are given the following;
Initial number of atoms of radium-226 as 8000 atoms
Time taken for the decay 3200 years
We are required to determine the number of atoms that will remain after 3200 years.
We need to know the half life of Radium
- Half life is the time taken by a radio active material to decay by half of its initial amount.
- Half life of Radium-226 is 1600 years
- Therefore, using the formula;
Remaining amount = Original amount × 0.5^n
where n is the number of half lives
n = 3200 years ÷ 1600 years
= 2
Therefore;
Remaining amount = 8000 atoms × 0.5^2
= 8000 × 0.25
= 2000 atoms
Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.
Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3
Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g
Answer:
The process of photosynthesis is commonly written as: 6CO2 + 6H2O → C6H12O6 + 6O2.
Explanation:
This means that the reactants, six carbon dioxide molecules and six water molecules, are converted by light energy captured by chlorophyll (implied by the arrow) into a sugar molecule and six oxygen molecules, the products.
Answer:
Explanation:
Hello!
In this case, according to the chemical reaction:
We can evidence the 2:1 mole ratio between hydrogen and tin, thus, we perform the following stoichiometric setup to obtain the mass of produced tin:
Best regards!
Answer:
Explanation:
a )
3NO₂(g) + H₂O(l) — -→ 2HNO₃(aq) + NO(g)
3 x 46 g 18 g 2 x 63 g 30 g
138 g of NO₂ requires 18 g of H₂O
28 g of NO₂ requires ( 18 / 138) x 28
= 3.65 g of H₂O.
b )
18 g of H₂O produces 30 g of NO gas
15.8 g of H₂O produces ( 30/18 ) x 15.8
= 26.33 g of NO gas .
c )
138 g of NO₂ produces 126 g of HNO₃
8.25 g of NO₂ produces (126 / 138 ) x 8.25
= 7.53 g of HNO₃
