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Lelechka [254]
3 years ago
7

Aluminum boils at 2467°C. Aluminum’s boiling point in Kelvin is 2194. True or False.

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

The given statement is false.

Explanation:

Given that aluminum boils at 2,467°C

Boiling point of aluminum in kelvins is 2,194 K

Temperature in degree Celsius can be converted into Kelvins by relation:

(T)^oC=273 +(T) K

So, boiling point of aluminium in Kelvins will be:

2,467 ^oC=273 +(2,467) K=2,740 K

2,740 K ≠ 2,194 K

But the given value in Kelvins is not coming equal to our calculated value, Hence, the given statement is false.

IceJOKER [234]3 years ago
3 0
False. To get Kelvin add 273 to <span>°C to get your temperature into Kelvin. The correct boiling point of Aluminum in Kelvin is 2740 K.</span>
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how many moles of silver nitrate are needed to produce 6.75 moles of copper (II) nitrate upon reacting with excess copper?
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3 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
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Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

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The chemical equation for the reaction of baking soda (sodium bicarbonate, nahco3) and vinegar (acetic acid, ch3cooh) may be wri
satela [25.4K]
<h3><u>Answer;</u></h3>

Step 1;  NaHCO3(s) + CH3COOH(l)

Step 2 ; CO2(g)

<h3><u>Explanation;</u></h3>
  • The chemical equation for the reaction of baking soda (sodium bicarbonate, NaHCO3) and vinegar (acetic acid, CH3COOH) reaction occurs in two steps.

Step 1;  

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  • Equation;

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Step 2;

  • Carbonic acid is unstable and undergoes a decomposition reaction to produce the carbon dioxide gas:

H2CO3(l) → H2O(l) + CO2(g)

3 0
3 years ago
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