One isomer is formed
1,1- Dichloroethane is the isomer.
If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.
- In contrast to 1,2-dichloroethane, which has two chlorine atoms connected to distinct carbon atoms, 1,1-dichloroethane has two chlorine atoms bound to the same carbon atom.
- Isomers are each of two or more compounds having the same formula but various atom arrangements in the molecule and unique characteristics.
<h3>What three types of isomers are there?</h3>
- Chain isomers
- Functional group isomers
- Positional isomers
These are the three different categories of structural isomers.
<h3>How is an isomer recognized?</h3>
- Their bonding patterns and the way they occupy three-dimensional space can be used to distinguish them.
- Determine the bonding patterns of structural (constitutional) isomers.
- Although the atoms in the compounds are the same, their connections create various functional groups.
<h3>What makes isomers significant?</h3>
- Because two isomers might have the same chemical formula but different chemical structures, they are significant.
- The molecule's properties are influenced by its structure.
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Aluminium belongs to 13th group of periodic table. It undergoes oxidation to given Al^+3 .
It is observed that when aluminium is added to a solution of copper sulphate the colour of the solution changes from blue to grey. It is due to formation of grey coloured solution of aluminium sulphate as
2Al^+3 + 3SO4^-2 ---> Al2(SO4)3
Explanation:
Sydney has been the work that is a great place 56 to be able and a day and day for a week or two types and we will have a very nice time of course but 6yy6667 has 7575665yy44y
Answer:
0.482 ×10²³ molecules
Explanation:
Given data:
Volume of gas = 2.5 L
Temperature of gas = 50°C (50+273 = 323 k)
Pressure of gas = 650 mmHg (650/760 =0.86 atm)
Molecules of N₂= ?
Solution:
PV= nRT
n = PV/RT
n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k
n = 2.15 atm. L /26.52 atm. mol⁻¹.L
n = 0.08 mol
Number of moles of N₂ are 0.08 mol.
Number of molecules:
one mole = 6.022 ×10²³ molecules
0.08×6.022 ×10²³ = 0.482 ×10²³ molecules
Answer:
the volume occupied by 3.0 g of the gas is 16.8 L.
Explanation:
Given;
initial reacting mass of the helium gas, m₁ = 4.0 g
volume occupied by the helium gas, V = 22.4 L
pressure of the gas, P = 1 .0 atm
temperature of the gas, T = 0⁰C = 273 K
atomic mass of helium gas, M = 4.0 g/mol
initial number of moles of the gas is calculated as follows;
The number of moles of the gas when the reacting mass is 3.0 g;
m₂ = 3.0 g
The volume of the gas at 0.75 mol is determined using ideal gas law;
PV = nRT
Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.
