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Otrada [13]
2 years ago
13

In this experiment you are directed to add a limited amount of NaOH (aq) and then an excess amount. A similar strategy will be u

sed with the addition of NH3(aq). Why? Group of answer choices Both NaOH and NH3 are weak bases. Both NaOH and NH3 are strong bases. Initially a metal hydroxide may form which becomes soluble when more base is added and the metal complex forms. Insoluble metal complexes are first formed which then are replaced by insoluble metal hydroxide precipitates. Initially a complex ion may form which becomes insoluble when more base is added and the metal hydroxide precipitate forms.
Chemistry
1 answer:
Verizon [17]2 years ago
7 0

The reason for adding a limited amount and then an excess amount is that initially a metal hydroxide may form which becomes soluble when more base is added and the metal complex forms.

In qualitative analysis is a common to add the base in drops and then in excess. When added in drops, the metal hydroxide is formed. This metal hydroxide is often insoluble.

After this metal hydroxide is formed, the base could be added in excess such that the metal hydroxide dissolves in the excess base by forming a complex.

For instance;

CuCl2(aq) + 2NaOH(aq)  -------> Cu(OH)2(s) + 2NaCl(aq)

Cu(OH)2(s) + 2OH^-(aq) -------> [Cu(OH)4]^2+(aq)

Learn more: brainly.com/question/1527403

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The chemical formula for ferric sulfate is Fe(SO4)3. Determine the following:
Lyrx [107]

Answer :

(a) The number of sulfur atoms are, 31.61\times 10^{23}.

(b) The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

Explanation :

(a) As we are given the number of moles of Fe_2(SO_4)_3 is, 1.75 mole. Now we have to calculate the number of sulfur atoms.

In the Fe_2(SO_4)_3, there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.

As, 1 mole of Fe_2(SO_4)_3 contains 3\times 6.022\times 10^{23} number of sulfur atoms.

So, 1.75 mole of Fe_2(SO_4)_3 contains 1.75\times 3\times 6.022\times 10^{23}=31.61\times 10^{23} number of sulfur atoms.

The number of sulfur atoms are, 31.61\times 10^{23}

(b) As we are given the number of moles of Fe_2(SO_4)_3 is, 2.65 mole. Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=2.65mole\times 399.88g/mole=1059.682g

The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) As we are given the mass of Fe_2(SO_4)_3 is, 3.45 grams. Now we have to calculate the moles of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

3.45g=\text{Moles of }Fe_2(SO_4)_3\times 399.88g/mole

\text{Moles of }Fe_2(SO_4)_3=8.63\times 10^{-3}mole

The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) As we are given the formula unit of Fe_2(SO_4)_3 is, 3. Now we have to calculate the mass of Fe_2(SO_4)_3.

As we know that 1 mole of Fe_2(SO_4)_3 contains 6.022\times 10^{23} formula unit.

Formula used :

\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

\text{Moles of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole

Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole\times 399.88g/mole=19.95\times 10^{-22}g

The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

6 0
3 years ago
Perform the following calculations to the correct number of significant figures.
SSSSS [86.1K]
Answer: 460.624

Explanation:
1. Multiply the numbers
(24.5260 x 2.56) + 397.84
= (62.784) + 397.84

2. Add the numbers
(62.784) + 397.84
= 460.624
4 0
2 years ago
guys im morgz im going to put a nail on the seat in my mom room and im going to see how up her a- s s it will go lets see
vagabundo [1.1K]

Answer:

go outside and ponder your life choices dork.

6 0
2 years ago
Which metal is more active than NI and less active than Zn?
Mademuasel [1]

Answer : The correct option is, (2) Cr (Chromium)

Explanation :

The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions. In the single displacement reaction, the most reactive metal displaces the least reactive metal.

From the given reactivity series we conclude that there are two metal (Mg and Cr) are more reactive metal than the Ni and there are two metal (Pb and Cr) are less reactive metal than the Zn. So, the Cr (Chromium) is the metal which is more active than Ni and less active than Zn.

Hence, the correct option is, (2) Cr

7 0
3 years ago
Read 2 more answers
A public School district furnishes pencils to its elementary school. The pencils the secretary orders from the district warehous
const2013 [10]

Answer:

The minimum number of boxes of pencils to be ordered is 630 boxes.

Explanation:

Since a pupil uses averagely 9.3 pencils

and a box contains 12 pencils,

the school enrollment is also 812

school's enrollment x average use of pencil per student

__________________________________________

            number of pencils in a box

812 x 9.3 = 7551.6

7551.6 /12 = 629.3

Having a total number of 630 boxes of pencils to be ordered.

3 0
2 years ago
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