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baherus [9]
4 years ago
15

What is the period of a spring that oscillates with a frequency of 2.09 Hz​

Physics
2 answers:
boyakko [2]4 years ago
7 0

Correct Answer:

0.4784 s

Sergio [31]4 years ago
5 0

Frequency, υ = 2.09 Hz

We know that time period, T = 1/υ

∴ T = 1 ÷ 2.09

⇒ T = 0.4784 seconds

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Please help! The image produced by a concave mirror is ? .
Alexeev081 [22]

Answer:

is a reflection.

The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted). When the object is that the focal point, the image is at infinity.

Explanation:

6 0
3 years ago
Read 2 more answers
A ball on the end of a string is revolving at a uniform rate in a vertical circle of radius 97.7 cm. If its speed is 3.74 m/s, a
noname [10]

The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

<h3>Tension</h3>

A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.

Tension in a string revolving can be determined using the expression;

T = mv² / r

Where m is mass of object, v is velocity and r is radius ( length of string )

Given the data in the question;

  • Mass of ball m = 0.182kg
  • Radius ( length of string ) r = 97.7cm = 0.977m
  • Velocity = 3.74m/s
  • Tension in the string; T = ?

To determine tension in the string, we substitute our given values into the expression above.

T = mv² / r

T = (0.182kg × (3.74m/s)²) / 0.977m

T = (0.182kg × 13.9876m²/s²) / 0.977m

T = (2.5457432kgm²/s²) / 0.977m

T = 2.61kgm/s²

T = 2.61N

Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

Learn more about Tension here: brainly.com/question/14351325

7 0
2 years ago
A rocket travels 1.3 km in 62 ms. What is its average speed in m⋅s−1? Do not give your answer in scientific notation. The answer
hjlf

Answer:

Average speed = 0.35 m/s

Explanation:

Given the following data;

Distance = 1.3 Km

Time = 62 minutes

To find the average speed in m/s;

First of all, we would convert the quantities to their standard unit (S.I) of measurement;

Conversion:

1.3 kilometres to meters = 1.3 * 1000 = 1300 meters

For time;

1 minute = 60 seconds

62 minutes = X

Cross-multiplying, we have;

X = 62 * 60

X = 3720 seconds

Now, we can calculate the average speed in m/s using the formula;

Speed = \frac {distance}{time}

Speed = \frac {1300}{3720}

Average speed = 0.35 m/s

7 0
3 years ago
The acceleration due to gravity on earth is 9.8m/s2. What is the weight of a 75 kg person on earth?
MissTica
Weight= 9.8*75=735N
OptionD
7 0
3 years ago
Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 478 N/C. If the particle
Gekata [30.6K]

Answer:

the speed of electron is 4.42 x 10⁶ m/s

the speed of proton is 2406.7 m/s

Explanation:

Given;

electric field strength, E = 478 N/C

charge of the particles, Q = 1.6 x 10⁻¹⁹ C

mass of proton, Mp = 1.673 x 10⁻²⁷ kg

mass of electron Me = 9.11 x 10⁻³¹ kg

time of motion, t = 54.2 ns = 54.2 x 10⁻⁹ s

The magnitude of charge experienced by the particles is calculated as;

F = EQ

F = 478 x 1.6 x 10⁻¹⁹

F = 7.648 x 10⁻¹⁷ N

The speed of the particles is calculated as;

F = \frac{mv}{t} \\\\v = \frac{Ft}{m} \\\\v_e = \frac{(7.684 \times 10^{-17})(52.4\times 10^{-9})}{9.11\times 10^{-31}} \\\\v_e = 4.42 \ \times \ 10^6 \ m/s

v_p = \frac{Ft}{m_p} \\\\v_p = \frac{(7.684 \times 10^{-17})(52.4\times 10^{-9})}{1.673\times 10^{-27}} \\\\v_p = 2406.7 \ m/s

7 0
3 years ago
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