3 years ago

Using the knowledge you gained from your lessons and from this practical exercise, this engine appears to be a

Physics

1 answer:

Travka [436]3 years ago

4 0

D)
(()(){({)({)(()({)())({)()({)()()()9

You might be interested in

If Frequency F, velocity v, and density D are considered fundamental units, the dimensional formula for momentum will be :

gizmo_the_mogwai [7]

Let's see

Momentum be P

$\\ \rm\Rrightarrow P=[Frequency]^a[velocity]^b[Density]^c$

$\\ \rm\Rrightarrow [P]=[F]^a[v]^b[D]^c$

$\\ \rm\Rrightarrow [M^1L^1T^{-1}]=[T^{-1}]^a[L^1T^{-1}]^b[M^1L^{-3}]^c$

$\\ \rm\Rrightarrow MLT^{-1}=T^{-a}L^bT^{-b}M^cL^{-3c}$

$\\ \rm\Rrightarrow MLT^{-1}=T^{-a-b}L^{b-3c}M^c$

On comaparing

b-3c=1
b-3=1
b=1+3
b=4

and

-a-b=-1
-a-4=-1
-a=-1+4=3
a=-3

So the unit is

DV⁴/F³

5 0

2 years ago

Read 2 more answers

a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported

oksano4ka [1.4K]

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as $q=It=(180\times 10^{-3})(5\times 60)= 54 C$ . It means that the number of electron that passes through the conductor is:

$n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}$

8 0

2 years ago

A car traveling north with a velocity of 33 m/sec slows down to a velocity of 12 m/sec north within 10 sec. What is the car’s de

strojnjashka [21]

a=v/t

v= 33-12 = 21

21÷10=2.1

a= 2.1

4 0

2 years ago

Read 2 more answers

A 0.5 kg rock is dropped from a height of 1.0 m above the ground. Approximately how much kinetic energy will be stored in the ro

irina1246 [14]

Answer:

2.45 J

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5 kg

Height (h) = 1 m

Kinetic energy (KE) =?

Next, we shall determine the velocity of the rock after it has fallen half way. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 1/2 = 0.5 m

Final velocity (v) =?

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 0.5)

v² = 9.8

Take the square root of both side

v = √9.8

v = 3.13 m/s

Finally, we shall determine the kinetic energy of the rock after it has fallen half way. This can be obtained as follow:

Mass (m) = 0.5 kg

Velocity (v) = 3.13 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.5 × 3.13²

KE = 0.25 × 9.8

KE = 2.45 J

Therefore, the kinetic energy of the rock after it has fallen half way is 2.45 J

8 0

3 years ago

Preschool girls and boys do not differ in the amount of muscle they have<br> 1) True<br> 2) False

Marina86 [1]

Explanation:

False...............

3 0

3 years ago