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Novosadov [1.4K]
3 years ago
5

Using the knowledge you gained from your lessons and from this practical exercise, this engine appears to be a

Physics
1 answer:
Travka [436]3 years ago
4 0
D)
(()(){({)({)(()({)())({)()({)()()()9
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Which bright object is in shadow
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My best guess would be sun because it is bright but is surrounded by shadows on all sides.
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3 years ago
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
kupik [55]

Answer:

2hrs and some mins

Explanation:

bc 2×36= 17 =)

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I need help on this
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6 0
3 years ago
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1.) because then people can evacuate the area in the path<span> of the hurricane.
2.) </span><span>At higher altitudes, water vapor starts to condense into clouds and rain, releasing heat that warms the surrounding air, Which makes it rise as well. Warmer waters feed more energetic storms.
3.) </span> <span>A hurricane starts off as a series of thunderstorms which intensify as it moves over the warm and humid sea. The humidity is at a constant level and so it continues to grow over the sea. Any kind of decrease or increase in humidity can change the strength of a hurricane. 
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</span><span>Annndd... 
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5 0
3 years ago
In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of
antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, a=84\ au= 1.496\times 10^{11}\ m

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e T^2=\dfrac{4\pi^2}{GM}a^3

where G is gravitational constant

M is  mass of sun, M=1.98\times 10^{30}\ Kg

So, T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}

T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3

T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}

T^2=59532469.8\times 10^{14}\ s

T=7715.7\times 10^7\ s

since, 1\ sec=3.17\times 10^{-8}\ years

So, orbital period is approximately 2446 years.

7 0
3 years ago
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