248, 428, 824, 284, 483, 842 are all numbers you can form with the 3 digits 2, 4, and 8
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\[\sum_{n=1}^{7} 2(-2)^{n-1}\]
Answer:
Find the midsegment of the triangle which is parallel to CA.
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
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Answer:
Multiplier = 1.75x (7/4).
7/8 cups butter, 4 and 3/8 ounces chocolate, 1 and 3/4 cups sugar, 7/8 teaspoons vanilla, 3 and 1/2 eggs (4 if rounded!), 1 and 5/16 cups flour.
Step-by-step explanation:
The ingredient list is for 16 brownies, but you need to make 28. This means you have to make 1.75x the amount (28/16), so all ingredient quantities need to be multiplied by 7/4 (1.75 in fraction form).
Butter: 1/2 * 7/4 = 7/8 cups
Chocolate: 5/2 * 7/4 = 4 and 3/8 ounces
Sugar: 1 * 7/4 = 1 and 3/4 cups
Vanilla: 1/2 * 7/4 = 7/8 teaspoons
Eggs: 2 * 7/4 = 3 and 1/2 eggs (if rounded, 4, as 3.5 rounds up)
Flour: 3/4 * 7/4 = 1 and 5/16 cups
