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3 years ago

I know the answer to number 7 but I just want to see if you guys know it

Mathematics

2 answers:

Nataly_w [17]3 years ago

6 0

1. 9(3)+3 = 27+3 = 30
2. 9( $8^{4}$ ) = 9(4096) = 36864
3. 9-6+3 = 6
4. 6(5)+30 = 30+30 = 60
5. 6( $8^{3}$ ) = 6(512) = 3072
6. ( $8^{3}$ )+84 = 512+84 = 596
7. 200+51 = 251
8. 3(18)+ $18^{2}$ = 54+324 = 378
9. 12(24)-36 = 288-36 = 252
10. 4(11+90)+10 = 44+280+10 = 334
11. 8-8 = 0
12.14(95)-1264+1 = 1330-1264+1 = 66+1 = 67

elixir [45]3 years ago

4 0

Plugging 10 for k in the expression gives us
$2(10)^2+5(10)+1$ We simplify this expression to $200+50+1=251$
251 is your answer

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Question 2

kari74 [83]

Answer:

7:55 am

Step-by-step explanation:

To determine the time needed to leave, add up all of the elapsed time and subtract that from the 8:50 departure time. The 10 minutes from walking to the platform puts us at 8:40 am, 30 minutes to reach the station puts us at 8:10 am, and the extra 15 minutes gives a time of 7:55 am.

4 0

2 years ago

Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i

Oxana [17]

Answer:

The probability that his coloring is factorific is 0.28125

Step-by-step explanation:

For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

2*2*2*2*2*2=64

Because we have 2 options to color every number.

For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

1: the divisor is 1

2: The divisors are 2 and 1

3: The divisors are 3 and 1

4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 2 * 2 * 2 = 8

number 1 number 2 number 3 number 4 number 5 number 6

At the same way we can calculate the following cases:

The number 2 is blue and the number 3 is red: If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 2 * 2 * 1 = 4

number 1 number 2 number 3 number 4 number 5 number 6

The number 2 is red and the number 3 is red: If the number 2 and 3 are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 1 * 2 * 1 = 2

number 1 number 2 number 3 number 4 number 5 number 6

The number 2 is red and the number 3 is blue: If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 1 * 2 * 2 = 4

number 1 number 2 number 3 number 4 number 5 number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

$P= \frac{18}{64} = 0.28125$