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Semmy [17]
3 years ago
8

Determine the slope of the line that contains the given points.

28-4%2C7%29" id="TexFormula1" title="G(-4,3), H(-4,7)" alt="G(-4,3), H(-4,7)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
stealth61 [152]3 years ago
6 0
I believe the slope is Undefined.
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Please tell me the answer quick
fomenos

Answer:

D) The expression 9 - p has exactly 2 terms

8 0
3 years ago
Can you say where to put each in different places in your answer? Please and thank you.
maw [93]
Coefficients are y and x
Variables are the number with the letters
The terms are the numbers
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2 years ago
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Ms. Lynette earns $19.50 an hour when she works overtime. She worked overtime twice this week. One day she worked 3 hours of ove
algol13
(19.50*3)+(19.50*x)=146.25
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Find a degree 3 polynomial with real coefficients having zeros 2 and 2 − 2 i and a lead coefficient of 1. Write P in expanded fo
Zanzabum

Answer:

The polynomial with real coefficients having zeros 2 and 2 - 2i is

x³ - 6x² + 16x - 16 = 0

Step-by-step explanation:

Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.

We have

x - 2 = 0

x - (2 - 2i) = 0

=> x - 2 + 2i = 0

Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.

x - (2 + 2i) = 0

=> x - 2 - 2i = 0

Now,

P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0

= (x - 2)((x - 2)² - (2i)²) = 0

= (x - 2)(x² - 4x + 8) = 0

= x³ - 4x² + 8x - 2x² + 8x - 16 = 0

= x³ - 6x² + 16x - 16 = 0

This is the polynomial required.

6 0
3 years ago
Confused on how to set the problem up.
MArishka [77]

Answer: idk but here's some advice re read the question if it says many your gonna add if it say how much then your subtracting and if it says something else then your multiplying or dividing so you have to do 5x133=665 so then that should be your answer


Step-by-step explanation:

Well imma have to keep spamming my question bc no one is even answering it :c


3 0
3 years ago
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