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LekaFEV [45]
3 years ago
8

(9x^4-3x^3+4x^2+5x+7) + (11x^4-4x^2-11x-9)

Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer:

20x^4 - 3x^3 - 6x - 2

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Brian started working at Domino’s in order to build his savings account. He started off with $33 dollars in his account, then ev
iragen [17]

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C

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Brandon buys a radio for $43.75 in a state where the sales tax is 7%.
Nastasia [14]

Answer:

Tax: $3.06

Step-by-step explanation:

7% of 43.75 = 0.07 × 43.75 = 3.0625

43.75 increase 7% =

43.75 × (1 + 7%) = 43.75 × (1 + 0.07) = 46.8125

Radio: $43.75

Tax: $3.06

Total: $46.81

4 0
2 years ago
Please help mee! &lt;33<br><br> y+4=-4(x+2)<br> in standard form! &lt;3
Pachacha [2.7K]

Answer:

y = -4x - 12

Step-by-step explanation:

y + 4 = -4(x + 2)

y = -4x -8 - 4

y = -4x - 12

6 0
2 years ago
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What fraction of 20 is 18?
Vera_Pavlovna [14]

Remark

You have to read this carefully to know what way to write it.

One way you could write it would be

20 * x = 18 where x is  the fraction. Now all you need do is divide.

Divide both sides by 20

20/20 * x = 18/20

\text{x = } \dfrac{18}{20}

But you should reduce this fraction. The way to do that is to factor 18 and 20 into primes.

18: 2 * 3 * 3

20: 2 * 2 *5

Cancel out the Highest common factor or 2.

You are left with

\text{x = } \dfrac{18}{20} =\dfrac{2*3*3}{2*2*5}=\dfrac{3*3}{2*5} = \dfrac{9}{10} <<<< Answer

4 0
3 years ago
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What Val are restricted from the domain of
djverab [1.8K]

<u>Given</u>:

The given expression is \frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

(2x-1)^2\neq 0

Taking square root on both sides, we get;

2x-1\neq 0

     2x\neq 1

      x\neq \frac{1}{2}

Thus, the restricted value from the domain is x\neq \frac{1}{2}

Hence, Option A is the correct answer.

7 0
3 years ago
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