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IRINA_888 [86]
4 years ago
14

1. Nuclear decay by alpha particle emission is more common in atoms of elements that:

Chemistry
1 answer:
11111nata11111 [884]4 years ago
3 0

Answer 1) Option a) have an atomic number greater than 83


Explanation : Nuclear decay by alpha particle emission is more common in atoms of elements that have an atomic number greater than 83. Nuclear reactions occurs with the elements which have mass number more than 200.


Answer 2) Option D) He^{4}_{2}


Explanation : In the given nuclear reaction of helium;


He^{3}_{2} + He^{3}_{2}  -----> He^{4}_{2} + 2 P^{1}_{1}


Two helium isotopes combines to give another helium isotope with emission of a proton (P).


Answer 3) Option D) The products are more radioactive than the reactants.


Explanation : The major drawback of a nuclear fission reaction to be used as an reliable energy source is that it usually produces the products which are found to be more radioactive than the reactants.


Answer 4) Option D) All of the above concerns.


Explanation : Nuclear reactions are usually very harmful in nature. It raises many concerns about the waste disposal that is generated from the reaction. It also requires safe operation for the working nuclear plants. It can also be misused for nuclear weapon proliferation. Hence, the answer is all of the above.


Answer 5) False.


Explanation : The energy output of the Sun and other stars is a result of fusion reactions among hydrogen nuclei. In fusion reactions usually additions takes place.


Answer 6) Option B) The "missing" mass has been converted to energy


Explanation : The total mass of a helium nucleus not equal to the mass of its individual parts because the missing mass has to be converted into energy.


Answer 7) Option A) less than the mass-energy of the products


Explanation : In a nuclear reaction, the mass-energy of the reactants is generally less than that of the mass-energy of the products because some energy has to be generated while the reaction is progressing.


Answer 8) Option D) 9.00 X 10^{17} J


Explanation : The calculation of the mass of 10.0 kilograms is completely converted into energy.


E = m X C^{2} formula can be used.


here m = 10 Kg and C = 3 X 10^{8} m/s



E = 10 X 3 X 10^{8} = 9.00 X 10^{17} J.


Answer 9) Option C) 3.60 X 10^{17} J.


Explanation : For calculation of energy for mass of 4 Kg


we can use the Einstein's formula,



E = m X C^{2}


where m = 4 Kg and C = C = 3 X 10^{8} m/s


E = 4 X 3 X 10^{8} = 3.60 X 10^{17} J.


Answer 10) False.


Einstein's formula for the conversion of mass and energy, to find the energy, multiply the mass by the speed of light squared.


E = m X C^{2}

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Answer:

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Explanation:

3 0
3 years ago
A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]
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<u>Explanation:</u>

To calculate the molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M

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                   C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-

<u>Initial:</u>           0.24          0.060              0.31

<u>Final:</u>             0.18          -                     0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

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pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89

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3.89=-\log[H_3O^+]

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Hence, the hydronium ion concentration in the solution is 1.29\times 10^{-4}M

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3 years ago
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1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

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