Answer:
-56
Step-by-step explanation:
Formula to get determinant is::
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)-8(7)
0 - 56
-56
Answer:
See explanation.
Step-by-step explanation:
First put 2x-4 equal to 0 and solve it.
2x-4=0
2x=4
x=2
Now plug 2 into the polynomial and see if it equals to 0
In case it's not, then it is not a factor of it
2(2)^5 - 4(2)^4 + 2x^2 -2(2) - 4 = 0
So it's indeed a factor of the polynomial.
Hope this helps!
The standard form for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix (d)
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)

y = 1/4 (x-1)^2 + 2