All categories

4 years ago

Pluto has a radius of 1.15 x 106 m

Physics

1 answer:

Nikitich [7]4 years ago

5 0

Answer:

$g=0.66\ m/s^2$

Explanation:

We have,

The radius of Pluto is $1.15\times 10^6\ m$

Mass of Pluto is $1.31\times 10^{22}\ kg$

It is required to find the acceleration of gravity on its surface. The formula used to find the acceleration is given by :

$g=\dfrac{Gm}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.31\times 10^{22}}{(1.15\times 10^6)^2}\\\\g=0.66\ m/s^2$

So, the acceleration due to gravity on Pluto is $0.66\ m/s^2$ .

You might be interested in

Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10

gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

$\Sigma \tau=0$

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

$-\tau_l+\tau_p+\tau_{cm}=0$ (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

$\tau=Fd$ (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

$-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N$

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

$F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N$

The force applied by the left support is 2123.33 N

8 0

4 years ago

Using the results of Question 1 that would apply if the collision were inelastic, compute (using Excel in the yellow highlighted

ch4aika [34]

Answer:

The fractional kinetic energy will be lost if the collision is inelastic. In inelastic collision, the kinetic energy is converted into other forms of energy.

The lost energy became heat and sound energy.

Explanation:

During inelastic collision, the kinetic energy of a moving object does not conserve. It changes into another form of energy such as sound energy and heat energy etc.

For example, when a moving car hit another car or wall etc, the kinetic energy is converted into sound and heat energy. This type of collision is inelastic collision.

4 0

3 years ago

What planet has a red surface

muminat

Answer:

Mars has a red surface the sun is solar

star so the only thing left is mars

Explanation:

Hope this helped :)

6 0

4 years ago

Read 2 more answers