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3 years ago

Pluto has a radius of 1.15 x 106 m

Physics

1 answer:

Nikitich [7]3 years ago

5 0

Answer:

$g=0.66\ m/s^2$

Explanation:

We have,

The radius of Pluto is $1.15\times 10^6\ m$

Mass of Pluto is $1.31\times 10^{22}\ kg$

It is required to find the acceleration of gravity on its surface. The formula used to find the acceleration is given by :

$g=\dfrac{Gm}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.31\times 10^{22}}{(1.15\times 10^6)^2}\\\\g=0.66\ m/s^2$

So, the acceleration due to gravity on Pluto is $0.66\ m/s^2$ .

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Answer:

Part a)

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Part b)

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Since the ball and rod is an isolated system and there is no external force on it so by momentum conservation we will have

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here we also use angular momentum conservation

so we have

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also we know that the collision is elastic collision so we have

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so we have

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also we know

$M v_o d - M v_1 d = \beta mL^2(\frac{v_o + v_1 - v_2}{d})$

also we know

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so we have

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Part b)

Now we know that speed of the ball after collision is given as

$v_1 = v_o - \frac{m}{M}v_2$

so it is given as

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3 years ago

Can anyone help me with this question please

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Explanation:

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v=final speed

u=initial speed,(starting speed)

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2a=6-2

2a=4

a=4/2 = 2

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2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

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v=24m/sec

5.v=u+at

=5+8*10

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V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

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