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tatyana61 [14]
3 years ago
12

What is the prefix notation of 0.0000738?​

Physics
2 answers:
mrs_skeptik [129]3 years ago
8 0

Answer:

The scientific notation of 738 is 7.38 x 1002.

OleMash [197]3 years ago
8 0
I agree with the answer above me…
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Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out
PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is  

\lambda _2 = (6.48,6.52) \ cm

Explanation:

From the question we are told that

     The wavelength of the note is \lambda  =  6.50 \ cm = 0.065 \ m

     The difference in beat frequency is \Delta  f = 17.0 \ Hz

     

Generally the frequency of the note played by the guitar that is in tune is  

        f_1 = \frac{v_s}{\lambda}

Where v_s is the speed of sound with a constant value v_s  =  343 \ m/s

       f_1 = \frac{343}{0.0065}

      f_1 = 5276.9 \ Hz

The difference in beat is mathematically represented as

       \Delta  f =  |f_1 - f_2|

Where f_2 is the frequency of the sound from the out of tune guitar

     f_2 =f_1  \pm \Delta f

substituting values

      f_2 =f_1 + \Delta f

      f_2 = 5276.9 + 17.0  

     f_2 = 5293.9 \ Hz

The wavelength for this frequency is

      \lambda_2 = \frac{343 }{5293.9}

     \lambda_2 = 0.0648 \ m

    \lambda_2 = 6.48 \ cm

For the second value of the second frequency

     f_2 =  f_1 - \Delta f

     f_2 = 5276.9 -17

      f_2 = 5259.9 Hz

The wavelength for this frequency is

   \lambda _2 = \frac{343}{5259.9}

   \lambda _2 = 0.0652 \ m

   \lambda _2 = 6.52 \ cm

8 0
3 years ago
Sergei uses a lever to lift a heavy rock. He obtains a 2.5m lever and places the fulcrum 0.7m from the rock. What is the ideal m
Anit [1.1K]

Answer:

m = 3.57

Explanation:

Given that,

Sergei uses a lever to lift a heavy rock. He obtains a 2.5m lever and places the fulcrum 0.7m from the rock.

We need to find the ideal mechanical advantage of Sergei's lever.

It is equal to the ratio of resistance arm to the effort arm. In terms of length it is given by :

m=\dfrac{d_2}{d_1}\\\\m=\dfrac{2.5}{0.7}\\\\=3.57

So, the ideal mechanical advantage of the lever is 3.57.

4 0
3 years ago
Can help slow down or stop the motion of an object
matrenka [14]
Net force can help slow down or stop the motion of an object.
6 0
3 years ago
A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t
Artyom0805 [142]

Answer:

D = 30.625 m

Explanation:

given,

Speed of the climber = 1.3 m/s

time = 2.5 s

acceleration due to gravity = 9.8 m/s²

initial speed of the kit = 1.3 m/s

velocity of the kit after 2.5 s

using equation of motion

v = u + a t

v = 1.3 + 9.8 x 2.5

v = 25.8 m/s

distance travel by the kit in 2.5 s

v² = u² + 2 g h

25.8² = 1.3² + 2 x 9.8 x h

19.6 h = 663.95

h = 33.875 m

distance travel by the rock climber in 2.5 s

distance = speed of climber x time

h' = 1.3 x 2.5

h' = 3.25 m

Distance between kit and rock climber

D = h - h'

D = 33.875 - 3.25

D = 30.625 m

The kit is 30.625 m below climber.

8 0
3 years ago
A 0.026 kg bullet is fired straight up at a falling wooden block that has a mass of 5.0 kg. The bullet has a speed of 750 m/s wh
Law Incorporation [45]

Answer:

0.198 s

Explanation:

Consider the motion of the block  before collision

v_{o} = initial velocity of block as it is dropped = 0 m/s

a = acceleration = - g

t = time of travel

v_{f} = final velocity of block before collision

Using the kinematics equation

v_{f} = v_{o} + at \\v_{f} = 0 + (-g)t\\v_{f} = - gt

m = mass of the bullet = 0.026 kg

v_{b} = velocity of block just before collision = 750 m/s

M = mass of the block = 5 kg

V = final velocity of bullet block after collision = gt

Using conservation of momentum

m v_{b} + Mv_{f} = (m + M) V\\(0.026) (750) + (5) (- gt) = (0.026 + 5) (gt)\\19.5 - 49 t = 49.2548 t\\t = 0.198 s

8 0
3 years ago
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